Definitely gonna be the 3rd one is your answer
B. Mn + NiBr₂ → Ni + MnBr₂
Explanation:
The reaction that can be predicted of all is Mn + NiBr₂ → Ni + MnBr₂.
The activity series is used to predict the products of single displacement reactions.
The series ranks metals in order of their reactivity. Those higher up in the series are highly reactive metals. Those at the bottom are slightly to non-reactive metals.
For a single displacement reaction to occur, a metal higher up in the activity series displaces one that is lower in the series.
Reaction A will not occur, Ba is higher in the series
Reaction C will not occur, Pt and Au are unreactive
Reaction D will not occur as Zn is lower in the series
Mn is higher in the reactivity series and it will displace Ni from the solution.
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Answer:
no.
Explanation:
The reason this has
never happened is due to the source of magnetic fields: moving electric
charges. When electric charges (e.g. electrons) move in circles, they
produce a magnetic field. In a piece of iron, it is very easy to line up
these circles, getting all the little magnets to work together as one big
magnet.
For each of these circles, one side is the north pole and one side is the
south pole. Since each circle has two sides, each circle has a north and a
south pole. Even the smallest possible magnets (spinning electrons) have a
north and a south pole.
Answer:
<h3>1)</h3>
Structure One:
Structure Two:
Structure Three:
Structure Number Two would likely be the most stable structure.
<h3>2)</h3>
- All five C atoms: 0
- All six H atoms to C: 0
- N atom: +1.
The N atom is the one that is "likely" to be attracted to an anion. See explanation.
Explanation:
When calculating the formal charge for an atom, the assumption is that electrons in a chemical bond are shared equally between the two bonding atoms. The formula for the formal charge of an atom can be written as:
.
For example, for the N atom in structure one of the first question,
- N is in IUPAC group 15. There are 15 - 10 = 5 valence electrons on N.
- This N atom is connected to only 1 chemical bond.
- There are three pairs, or 6 electrons that aren't in a chemical bond.
The formal charge of this N atom will be
.
Apply this rule to the other atoms. Note that a double bond counts as two bonds while a triple bond counts as three.
<h3>1)</h3>
Structure One:
Structure Two:
Structure Three:
In general, the formal charge on all atoms in a molecule or an ion shall be as close to zero as possible. That rules out Structure number one.
Additionally, if there is a negative charge on one of the atoms, that atom shall preferably be the most electronegative one in the entire molecule. O is more electronegative than N. Structure two will likely be favored over structure three.
<h3>2)</h3>
Similarly,
- All five C atoms: 0
- All six H atoms to C: 0
- N atom: +1.
Assuming that electrons in a chemical bond are shared equally (which is likely not the case,) the nitrogen atom in this molecule will carry a positive charge. By that assumption, it would attract an anion.
Note that in reality this assumption seldom holds. In this ion, the N-H bond is highly polarized such that the partial positive charge is mostly located on the H atom bonded to the N atom. This example shows how the formal charge assumption might give misleading information. However, for the sake of this particular problem, the N atom is the one that is "likely" to be attracted to an anion.