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zzz [600]
2 years ago
10

During evaporation, the volume of the liquid decreases and the liquid becomes what??? ​

Chemistry
1 answer:
oee [108]2 years ago
4 0

Answer:

Evaporation happens when a liquid substance becomes a gas. When water is heated, it evaporates. The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor. ... Once water evaporates, it also helps form clouds

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Give the answer to the problem below using the correct number of significant digits. (1.3 x 103) x (5.724 x 104)
Gemiola [76]
(133.9) x (595.296)= 79,710.1344
Answer with significant digits: 80,000
1.3 has two significant digits so 79,700 rounds up to 80000.
6 0
3 years ago
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In a sulphuric acid (h2so4) - sodium hydroxide (naoh) acid-base titration, 17.3 ml of 0.126 m naoh is needed to neutralize 25 ml
katen-ka-za [31]
The balanced equation for the neutralisation reaction is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
the number of moles of NaOH reacted  - 0.126 mol/L  x 0.0173 L = 0.00218 mol
if 2 mol of NaOH reacts with 1 mol of H₂SO₄ 
then 0.00218 mol of NaOH reacts with - 0.00218 / 2 = 0.00109 mol of H₂SO₄ 
molarity is the number of moles of solute in 1 L solution
therefore if 25 mL contains - 0.00109 mol 
then 1000 mL contains - 0.00109 mol / 25 mL  x 1000 mL = 0.0436 mol/L
therefore molarity of H₂SO₄ is 0.0436 M
4 0
3 years ago
describe characteristics of different climate zones as they relate to latitude,elevation,and proximity to bodies of water. (scie
g100num [7]
They or on the southern hysteric watch it on youtube (latitude and longitude song 1 direction remix by the history teachers)
7 0
2 years ago
For the equilibrium
Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

H_2S=0.596M

H_2=0.004 M

S_2=0.002 M

Explanation:

We are given that  for the equilibrium

2H_2S\rightleftharpoons 2H_2(g)+S_2(g)

k_c=9.0\times 10^{-8}

Temperature, T=700^{\circ}C

Initial concentration of

H_2S=0.30M

H_2=0.30 M

S_2=0.150 M

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles  of reactant reduced and form product

Concentration of

H_2S=0.30+2x

H_2=0.30-2x

S_2=0.150-x

At equilibrium

Equilibrium constant

K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Substitute the values

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

By solving we get

x\approx 0.148

Now, equilibrium concentration  of gases

H_2S=0.30+2(0.148)=0.596M

H_2=0.30-2(0.148)=0.004 M

S_2=0.150-0.148=0.002 M

3 0
2 years ago
Oxygen Supply in Submarines Nuclear submarines can stay under water nearly indefinitely because they can produce their own oxyge
andrew11 [14]

Answer:

0.025 L

Explanation:

The production of oxygen in the electrolysis of water is;

4OH^-(aq) -----> 2H2O(l) + O2(g) + 4e

Since 1 F = 96500C

molar volume of a gas = 22.4 L

From the reaction equation;

4 * 96500 C yields 22.4 L of oxygen

(3 * 60 * 60 *  0.0400) C yields (3 * 60 * 60 *  0.0400) * 22.4/4 * 96500

= 9676.8/386000

= 0.025 L

3 0
2 years ago
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