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lutik1710 [3]
3 years ago
5

What mass of nitrous oxide gas (N2O) is contained in 20.0 L balloon at a pressure of 110.0 kPa and a temperature of 25 C?

Chemistry
1 answer:
likoan [24]3 years ago
3 0

Answer:

40.94 g

Explanation:

Given data:

Mass of NO₂ = ?

Volume = 20.0 L

Pressure = 110.0 Pka

Temperature = 25°C

Solution:

Pressure = 110.0 KPa (110/101 = 1.1 atm)

Temperature = 25°C (25+273 = 298.15 K)

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

n = PV/RT

n = 1.1 atm × 20.0 L / 0.0821 atm.L/ mol.K ×298.15 K

n = 22 / 24.5 /mol

n= 0.89 mol

Mass of NO₂:

Mass = number of moles × molar mass

Mass = 0.89 mol × 46 g/mol

Mass = 40.94 g

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7 0
3 years ago
1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2 Torr at 25 °C) form ideal solutions in all proportions. Let x1
jekas [21]

Answer:

y1 = 0.3162

y2 = 0.6838

Explanation:

ok let us begin,

first we would be defining the parameters;

at 25°C;

1-propanol P1° = 20.90 Torr

2-propanol P2° = 45.2 Torr

From Raoults law:

P(1-propanol) = P⁰ × X(1-propanol)

P(1-propanol) = 20.9 torr × 0.45 = 9.405

P(1-propanol) = 9.405 torr

Also P(2-propanol) = P⁰ × X(2-propanol)

P(2-propanol) = 45.2 torr × 0.45

P(2-propanol) = 20.34 torr

but the total pressure = sum of individual pressures

total pressure = 9.405 + 20.34

total pressure = 29.745 torr

given that y1 and y2 represent the mole fraction of each in the vapor phase

y1 = P1 / total pressure

y1 = 9.405/29.745

y1 = 0.3162

Since y1 + y2 = 1

y2 = 1 - y1

∴ y2 = 1 -  0.3162

y2 = 0.6838

cheers, i hope this helps.

7 0
3 years ago
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