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laiz [17]
3 years ago
13

A mass of 1.5 kg is attached to a spring and placed on a horizontal surface. The spring has a spring constant of 120 N/m, and th

e spring is compressed 0.25 m past its natural length. If the mass is released from this compressed position, what is the speed of the mass as it passes the natural length of the spring? A. 3.4 m/s B. 1.5 m/s C. 0.99 m/s D. 2.2 m/s
Physics
2 answers:
dusya [7]3 years ago
8 0
I even need this ! Help me tooooooooo Thanks  HAve a good day
IrinaK [193]3 years ago
4 0

Answer:

Speed of the mass is 2.2 m/s

Explanation:

It is given that,

Mass of the object, m = 1.5 kg

Spring constant of the spring, k = 120 N/m

The spring is compressed by a distance of, x = 0.25 m

The mass is released from this compressed position, then the initial kinetic energy of block is equal to the spring potential energy i.e.

\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2

v is the speed of the mass.

v=\sqrt{\dfrac{kx^2}{m}}

v=\sqrt{\dfrac{120\times (0.25)^2}{1.5}}

v = 2.23 m/s

The speed of the mass as it passes the natural length of the spring is 2.2 m/s. Hence, the correct option is (d).            

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Cesium-137 undergoes beta decay and has a half-life of 30.0 years. How many beta particles are emitted by a 14.0-g sample of ces
Mandarinka [93]

Answer: 0.81\times 10^{16} beta particles

Explanation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 14.0 g

Molar mass = 137 g/mol

\text{Number of moles of cesium}=\frac{14.0g}{137g/mol}=0.102moles

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of cesium contains atoms =  6.023\times 10^{23}

0.102 moles of cesium contains atoms =  \frac{6.023\times 10^{23}}{1}\times 0.102=0.614\times 10^{23}

The relation of atoms with time for radioactivbe decay is:

N_t=N_0\times \frac{1}{2}^{\frac{t}{t_{\frac{1}{2}}}}

Where N_t =atoms left undecayed

N_0 = initial atoms

t = time taken for decay = 3 minutes

{t_{\frac{1}{2}}} = half life = 30.0 years = 1.577\times 10^7 minutes

The fraction that decays  :  1-(\frac{1}{2})^{\frac{3}{1.577\times 10^7}}=1.32\times 10^{-7}

Amount of particles that decay is  = 0.614\times 10^{23}\times 1.32\times 10^{-7}=0.81\times 10^{16}

Thus 0.81\times 10^{16} beta particles are emitted by a 14.0-g sample of cesium-137 in three minutes.

7 0
3 years ago
List of three questions that you are good at science questions.
Klio2033 [76]

Answer:

cycles, graphing, precise measurementation

Explanation:

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A 782.10 kg car is brought from 7.60 m/s to 3.61 m/s over a time period of 4.23 seconds. What is the average force the car exper
alexandr402 [8]

Answer:

–735.17 N

The negative sign indicate that the force is acting in opposition direction to the car.

Explanation:

The following data were obtained from the question:

Mass (m) of car = 782.10 kg

Initial velocity (u) = 7.60 m/s

Final velocity (v) = 3.61 m/s

Time (t) = 4.23 s

Force (F) =?

Next, we shall determine the acceleration of the car. This can be obtained as follow:

Initial velocity (u) = 7.60 m/s

Final velocity (v) = 3.61 m/s

Time (t) = 4.23 s

Acceleration (a) =?

a = (v – u) / t

a = (3.61 – 7.60) / 4.23

a = –3.99 / 4.23

a = –0.94 m/s²

Finally, we shall determine the force experienced by the car as shown below:

Mass (m) of car = 782.10 kg

Acceleration (a) = –0.94 m/s²

Force (F) =?

F = ma

F = 782.10 × –0.94

F = –735.17 N

The negative sign indicate that the force is acting in opposition direction to the car.

4 0
3 years ago
Worth 50 point!!!
stira [4]

Answer:

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Explanation:

fact two is going slower and a longer distance than fact one so fact one will get there first.

hope this helps

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Which type of rock can only form below earths surface?
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Answer: Igneous it forms because of magma but magma is under the earths surface so its Igneous

Explanation:

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