Ask question

Ask question

All categories

3 years ago

13

A mass of 1.5 kg is attached to a spring and placed on a horizontal surface. The spring has a spring constant of 120 N/m, and th

e spring is compressed 0.25 m past its natural length. If the mass is released from this compressed position, what is the speed of the mass as it passes the natural length of the spring? A. 3.4 m/s B. 1.5 m/s C. 0.99 m/s D. 2.2 m/s

2 answers:

dusya [7]3 years ago

8 0

I even need this ! Help me tooooooooo Thanks HAve a good day

IrinaK [193]3 years ago

4 0

Answer:

Speed of the mass is 2.2 m/s

Explanation:

It is given that,

Mass of the object, m = 1.5 kg

Spring constant of the spring, k = 120 N/m

The spring is compressed by a distance of, x = 0.25 m

The mass is released from this compressed position, then the initial kinetic energy of block is equal to the spring potential energy i.e.

$\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2$

v is the speed of the mass.

$v=\sqrt{\dfrac{kx^2}{m}}$

$v=\sqrt{\dfrac{120\times (0.25)^2}{1.5}}$

v = 2.23 m/s

The speed of the mass as it passes the natural length of the spring is 2.2 m/s. Hence, the correct option is (d).

You might be interested in

A 525 kg satellite is in a circular orbit at an altitude of 575 km above the Earth's surface. Because of air friction, the satel

Dafna1 [17]

Answer:

$1.69\cdot 10^{10}J$

Explanation:

The total energy of the satellite when it is still in orbit is given by the formula

$E=-G\frac{mM}{2r}$

where

G is the gravitational constant

m = 525 kg is the mass of the satellite

$M=5.98\cdot 10^{24}kg$ is the Earth's mass

r is the distance of the satellite from the Earth's center, so it is the sum of the Earth's radius and the altitude of the satellite:

$r=R+h=6370 km +575 km=6945 km=6.95\cdot 10^6 m$

So the initial total energy is

$E_i=-(6.67\cdot 10^{-11})\frac{(525 kg)(5.98\cdot 10^{24} kg)}{2(6.95\cdot 10^6 m)}=-1.51\cdot 10^{10}J$

When the satellite hits the ground, it is now on Earth's surface, so

$r=R=6370 km=6.37\cdot 10^6 m$

so its gravitational potential energy is

$U = -G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(525 kg)(5.98\cdot 10^{24}kg)}{6.37\cdot 10^6 m}=-3.29\cdot 10^{10} J$

And since it hits the ground with speed

$v=1.90 km/s = 1900 m/s$

it also has kinetic energy:

$K=\frac{1}{2}mv^2=\frac{1}{2}(525 kg)(1900 m/s)^2=9.48\cdot 10^8 J$

So the total energy when the satellite hits the ground is

$E_f = U+K=-3.29\cdot 10^{10}J+9.48\cdot 10^8 J=-3.20\cdot 10^{10} J$

So the energy transformed into internal energy due to air friction is the difference between the total initial energy and the total final energy of the satellite:

$\Delta E=E_i-E_f=-1.51\cdot 10^{10} J-(-3.20\cdot 10^{10} J)=1.69\cdot 10^{10}J$

8 0

3 years ago

The average coefficient of linear expansion of copper is 1.7 10-5 (°c)−1. the statue of liberty is 93 m tall on a summer morning

sammy [17]

Let the rise in temperature be $5^0C$

The expansion in length due to change in temperature is given by the expression lαΔt , where l is the length, α is the coefficient of linear expansion, Δt is the change in temperature.

Here l = 93 m, α = $1.7*10^{-5}$ $^0C^{-1}$ , and Δt = $5^0C$

So expansion in length = 93* $1.7*10^{-5}$ *5 = 0.007905 m = $0.79*10^{-3}m$

So order of magnitude in change in length = -3

3 0

2 years ago

Read 2 more answers

Which things determine an element's electronegativity? Check all that apply. A. The size of the atom of that element B. Whether

KengaRu [80]

D. The number of electrons

6 0

2 years ago

Monochromatic light of wavelength 580 nm passes through a single slit and the diffraction pattern is observed on a screen. Both

Nuetrik [128]

Answer:

Part a)

Width of the slit is

$a = 580 nm$

Part b)

Ratio of intensity is given as

$\frac{I}{I_o} = 0.81$

Explanation:

Part a)

As we know by the formula of diffraction we will have

$a sin\theta = \lambda$

so we have

$\theta = 90$

$\lambda = 580 nm$

so we will have

$a sin90 = 580 nm$

$a = 580 nm$

Part b)

As we know that the intensity in diffraction pattern is given as

$I = I_o (\frac{sin\theta}{\theta})^2$

$\frac{I}{I_o} = (\frac{sin\theta}{\theta})^2$

so for angle 45 degree

$\frac{I}{I_o} = (\frac{sin45}{\pi/4})^2$

$\frac{I}{I_o} = (\frac{sin45}{\pi/4})^2$

$\frac{I}{I_o} = 0.81$

7 0

3 years ago

Crystals are made using supersaturated solutions of solids in water.

labwork [276]

The way these supersaturated solutions are made is: A. The water would need to be heated to a higher temperature, which would give molecules and ions more kinetic energy, increasing solubility.

Solubility is simply a measure of how readily a substance is able to dissolve in a solvent to form a solution. Thus, a substance is soluble when it dissolves completely in a solvent and it is considered to be insoluble when it does not dissolve in a solvent or if it only dissolves partially.

A supersaturated solution can be defined as a solution that contains more solute than the equilibrium amount.

Generally, supersaturated solutions of solids in water are typically used for the creation of crystals because they are able to hold more of the solute than they would at room temperature.

In order to create these supersaturated solutions, the water should be heated to a higher temperature, so that the water molecules and ions can gain more kinetic energy and thereby increasing solubility.

In conclusion, heating the water to a higher temperature causes the water molecules and ions to gain more kinetic energy and thereby increasing solubility..

Read more: brainly.com/question/24058779

8 0

3 years ago

Read 2 more answers