<h2>precipitation reactions</h2>
α prєcípítαtíσn rєαctíσn rєfєrs tσ thє fσrmαtíσn σf αn ínsσluвlє sαlt whєn twσ sσlutíσns cσntαíníng sσluвlє sαlts αrє cσmвínєd. thє ínsσluвlє sαlt thαt fαlls σut σf sσlutíσn ís knσwn αs thє prєcípítαtє, hєncє thє rєαctíσn's nαmє. prєcípítαtíσn rєαctíσns cαn hєlp dєtєrmínє thє prєsєncє σf vαríσus íσns ín sσlutíσn.
Answer:
The acceleration of car is 6.67 m/s².
Explanation:
Given that,
Initial velocity = 30 m/s
Distance = 15 m
Final velocity = 10 m/s
Time = 3 sec
We need to calculate the acceleration
Using formula of acceleration




Negative sign shows the car is slowing down.
Hence, The acceleration of car is 6.67 m/s².
Answer:
Option D
0.83 m/s2
Explanation:
Time is assumed as 10 seconds
First, convert the speeds from km/h to m/s
20 km/h\times \frac {1000 m}{3600 s}=5.555555556 m/s
\approx 5.56 m/s
50 km/h\times \frac {1000 m}{3600 s}=13.88888889 m/s \approx 13.89 m/s
Acceleration,
where u and v are the initial and final velocities respectively, t is the time taken to accelerate.
Substituting 13.89 m/s for v, 5.56 m/s for u and 10 s for t then

N=m.g
N=72 x 9.8 = 705.6 ≈ 706 N