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forsale [732]
2 years ago
5

Pleasehelpmewith this problem​

Physics
1 answer:
uranmaximum [27]2 years ago
3 0

Answer:

speeding up

Explanation:

because its speeding up, theres going to be more newtons in the back

i really hope this is right, tell me if so

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When you float an ice cube in water, you notice that 90% of it is submerged beneath the surface. Now suppose you put the same ic
Gwar [14]

Answer:

option (c)

Explanation:

90% of the body is submerged in water.

Now it is immersed in an unknown liquid whose density is less than the density of water.

Buoyant force acting on the body depends on the volume immersed, density of liquid and gravity.

As the density of liquid is less than the density of water, so the buoyant force acting on the body by the unknown liquid is less than water. So it is submerged less than 90% in this liquid.

6 0
3 years ago
A slice of pizza has 500 kcal. If we could burn the pizza and use all the heat to warm a 50-L container of cold water, what woul
topjm [15]

Answer:

increase in temperature of water is 10° C

Explanation:

Given data

pizza = 500 kcal = 500000 calories

cold water = 50 L

to find out

increase in temperature of water

solution

we know heat formula that is

heat = m × specific heat × Δt

here m is mass = 50000 gram and Δt is change in temperature

and specific heat = 1 cal / gram C

so put here all value and find Δt

500000 = 50000 × 1  × Δt

Δt = 10° C

so increase in temperature of water is 10° C

4 0
3 years ago
Read 2 more answers
Where are protons and neutrons found in an atom
mr Goodwill [35]

Answer:

The Nucleus

Explanation:

Protons and Neutrons are found in the nucleus of an atom.

3 0
3 years ago
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A 1.50 µF capacitor and a 3.50 µF capacitor are connected in series across a 2.50 V battery. How much charge (in µC) is stored o
Nataly_w [17]

Explanation:

The given data is as follows.

      C_{1} = 1.50 \times 10^{-6} F

      C_{1} = 3.50 \times 10^{-6} F    

      Voltage = 2.50 V

Hence, calculate the equivalence capacitor as follows.

    \frac{1}{C} = \frac{1}{C_{1}} + \frac{1}{C_{2}}

    \frac{1}{C} = \frac{1}{1.50 \times 10^{-6} F} + \frac{1}{3.50 \times 10^{-6} F}

                 = 0.945 \times 10^{-6} F

          C = 1.06 \times 10^{-6} F

Now, we will calculate the charge across each capacitance as follows.

              Q = CV

                  = 1.06 \times 10^{-6} F \times 2.50 V

                  = 2.65 \times 10^{-6} C

                  = 2.65 \mu C

Thus, we can conclude that 2.65 \mu C is the charge stored on each given capacitor.

5 0
3 years ago
What happens when water is heated for long?​
Y_Kistochka [10]

Answer: it becomes steam

Explanation:

3 0
3 years ago
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