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forsale [732]
2 years ago
5

Pleasehelpmewith this problem​

Physics
1 answer:
uranmaximum [27]2 years ago
3 0

Answer:

speeding up

Explanation:

because its speeding up, theres going to be more newtons in the back

i really hope this is right, tell me if so

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Which of these are broken down during chemical, but not physical, changes?
Doss [256]

I think your answer is D

because you already said its not a B is a liquid and  not a solid so its harder to have a chemical change C is solutions and D is compound and I know for a fact that a compound is a solid and if C is also a solid then that could also be a possible answer choice.

5 0
3 years ago
A girl scout is pulling her 30 kg wagon of cookies with a force of 60 N to right. Friction pulls back with a force of 15 N left.
andreyandreev [35.5K]

Answer:

net force = 45 newton towards right

8 0
3 years ago
two astronauts are taking a spacewalk outside the International Space Station the first astronaut has a mass of 64 kg the second
Fittoniya [83]

Answer:

Approximately 0.88\; {\rm m \cdot s^{-1}} to the right (assuming that both astronauts were originally stationary.)

Explanation:

If an object of mass m is moving at a velocity of v, the momentum p of that object would be p = m\, v.

Since momentum of this system (of the astronauts) conserved:

\begin{aligned} &(\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\end{aligned}.

Assuming that both astronauts were originally stationary. The total initial momentum of the two astronauts would be 0 since the velocity of both astronauts was 0\!.

Therefore:

\begin{aligned} &(\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\\ &= 0\end{aligned}.

The final momentum of the first astronaut (m = 64\; {\rm kg}, v = 0.8\; {\rm m\cdot s^{-1}} to the left) would be p_{1} = m\, v = 64\; {\rm kg} \times 0.8\; {\rm m\cdot s^{-1}} = 51.2\; {\rm kg \cdot m \cdot s^{-1}} to the left.

Let p_{2} denote the momentum of the astronaut in question. The total final momentum of the two astronauts, combined, would be (p_{1} + p_{2}).

\begin{aligned} & p_{1} + p_{2} \\ &= (\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\\ &= 0\end{aligned}.

Hence, p_{2} = (-p_{1}). In other words, the final momentum of the astronaut in question is the opposite of that of the first astronaut. Since momentum is a vector quantity, the momentum of the two astronauts magnitude (51.2\; {\rm kg \cdot m \cdot s^{-1}}) but opposite in direction (to the right versus to the left.)

Rearrange the equation p = m\, v to obtain an expression for velocity in terms of momentum and mass: v = (p / m).

\begin{aligned}v &= \frac{p}{m} \\ &= \frac{51.2\; {\rm kg \cdot m \cdot s^{-1}}}{64\; {\rm kg}} && \genfrac{}{}{0}{}{(\text{to the right})}{} \\ &\approx 0.88\; {\rm m\cdot s^{-1}} && (\text{to the right})\end{aligned}.

Hence, the velocity of the astronaut in question (m = 58.2\; {\rm kg}) would be 0.88\; {\rm m \cdot s^{-1}} to the right.

5 0
2 years ago
Which expression is equivalent to g−m ÷ gn?
Vinvika [58]

<u>Answer</u>

(g²n - m)/(gm)


<u>Explanation</u>

g - m ÷ gn = g - m/gn  

Make the equation have the same denominator

  g - m ÷ gn = g - m/gn    = (ggn)/gn  - m/gn

                                          = (g²n)/gn - m/gm

Since they have the same denominator, we can carry out the subtraction on the numerator and then put them under one denominator.

                                      (g²n)/gn - m/gm  = (g²n - m)/(gm)


5 0
3 years ago
Determine the acceleration of a boat<br> with a speed of 18 m/s for 20 seconds.
seropon [69]

Answer:

Explanation:

initial velocity, u = 0

final velocity, v = 18 m/s

time = 20 sec

acceleration, a = v - u / t

= 18 - 0 / 20

= 18 / 20

= 9 / 10

= 0.9 m/s^2

Hope this helps

plz mark as brainliest!!!!!!

5 0
3 years ago
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