Explanation:
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Answer:
Explanation:
The work (W) done on the cube to be pushed across the floor is equal to the total thermal energy (ΔE) of the system:
(1)
Also, the work done on the cube by the horizontal force is giving by:
(2)
<em>where F: force applied to the cube , d: displacement of the cube </em>
<em>By equaling the equations (1) and (2)</em>, we can find the thermal energy of the floor:
So, the increase in the thermal energy of the floor is 51 J.
Have a nice day!
This question is incomplete, the complete question is;
A parallel-plate capacitor is made from two aluminum-foil sheets, each 3.0 cm wide and 5.00 m long. Between the sheets is a mica strip of the same width and length that is 0.0225 mm thick. What is the maximum charge?
(The dielectric constant of mica is 5.4, and its dielectric strength is 1.00×10⁸ V/m)
Answer: the maximum charge q is 716.85 μF
Explanation:
Given data;
with = 3.0 cm = 0.03
breathe = 5.0 m
Area = 0.03 × 5 = 0.15 m²
dielectric strength E = 1.00 × 10⁸
∈₀ = 8.85 × 10⁻¹²
constant K = 5.4
maximum charge = ?
the capacitor C = KA∈₀ / d
q = cv so c = q/v
now
q/v = KA∈₀ / d
q = vKA∈₀/d = EKA∈₀
we substitute
q = (1.00 × 10⁸) × 5.4 × 0.15 × 8.85 × 10⁻¹²
q = 716.85 × 10⁻⁶ F
q = 716.85 μF
the maximum charge q is 716.85 μF
Answer: two electrons
Explanation: The first principal energy level contains only an s sublevel; therefore, it can hold a maximum of two electrons. Each principal energy level above the first contains one s orbital and three p orbitals. A set of three p orbitals, called the p sublevel, can hold a maximum of six electrons.
