Help me asap!!!thanks

The endpoints of PQ are P(2, 0) and Q (4, 2). Find the coordinates of midpoint PQ.

lawyer [7]

Answer:

Step-by-step explanation:

Parameterize the ellipse as (acos∙,bsin∙). Take points P:=(acosp,bsinp) and Q:=(acosq,bsinq) on the ellipse, with midpoint M:=(P+Q)/2.

If |PQ|=2k, then

a2(cosp−cosq)2+b2(sinp−sinq)2=4k2

The coordinates of M are

xy==a2(cosp+cosq)b2(sinp+sinq)

4 0

4 years ago

Identify the variable expression that is not a polynomial.

Blababa [14]

I think the answer is A.33 not a polunomial

6 0

3 years ago

Read 2 more answers

What is the slope of the line represented by the equation?<br> –2x + y = –1

Harrizon [31]

Isolate the y to one side so we get: y = 2x - 1
The slope of the line is 2.

8 0

2 years ago

Read 2 more answers

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

as

$\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81$

$\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x$

$\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2$

$\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3$

$\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4$

so equation becomes

$=81+108x+54x^2+12x^3+x^4$

$=x^4+12x^3+54x^2+108x+81$

Therefore,

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

6 0

3 years ago

emily read 24 fiction books and 2 nonfiction books. what is the ratio of the number of fiction books she read to the total numbe

Elis [28]

Answer:

24:26 or 12:13

Step-by-step explanation:

Ratios can be better understood if you read 24:26 as: Emily read 24 fiction books for every 26 books.

The question tells us Emily read 24 fiction books and 2 nonfiction books. We know she read 24 fiction books so that is the first part of our ratio. Now, they want to know how many total books did she read. Well, she read 24 fiction and 2 nonfiction. 24+2 = 26. 26 books total! So now we have the second part of our ratio and end up with the ratio of 24:26. But now, we have to simplify it. Simplifying ratios is like simplyfing fractions. You have to find their greatest common factor. The greatest common factor of 24 and 26 is 2. Now you divide both number by their greatest common factor (2). Finally, we end up with the ratio of 12:13.

Greatest common factor help: https://www.mathsisfun.com/greatest-common-factor.html

7 0

3 years ago