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Inessa05 [86]
3 years ago
13

Help me asap!!!thanks

Mathematics
1 answer:
Elza [17]3 years ago
3 0

Answer: 55cm^2

Step-by-step explanation:Area of a parallelogram= bh, so the base and height for this new one are base of 11 and height 5. so 11*5=55

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Which is expression is equivalent to 7(x+4)
Pepsi [2]

Answer:7x+28

Step-by-step explanation:

7×x = 7x

7×4 = 28

8 0
3 years ago
What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the
marishachu [46]
The sum of all the measurements is just the average times the number.

\bar x = \frac{1}{n} \sum_{i=1}^n x_i

\sum_{i=1}^n x_i = n \bar x

So if the average of all 92 is 7 the sum of those is 92 \times 7

The average of the last two is 7.2 so their sum is 2 \times 7.2

That means the sum of the first 90 is 92 \times 7 - 2 \times 7.2

so the average of the first 90 is

 \dfrac{92 \times 7 - 2 \times 7.2}{90} = 6.99556 cm



7 0
3 years ago
What is the value of x and y?
crimeas [40]

Answer:

C. x = 8 , y = 40

Step-by-step explanation:

since this is an Isosceles triangle 5x = 40° and x = 8

The sum of interior angles in a triangle is equal to 180°

40° + 5x + 2y + 20 = 180° add like terms

5x + 2y = 120

40 + 2y = 120 ➡ 2y = 80 and y = 40

8 0
3 years ago
Read 2 more answers
Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.
Lelechka [254]

Answer:

1) \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}} = 32

Step-by-step explanation:

1) \frac{(-2)^{-5}}{(-2)^{-10}}

Solving using exponent rule: a^{-m}=\frac{1}{a^m}

\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32

So, \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4}

Using the exponent rule: a^m.a^n=a^{m+n}

We have:

2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}

We also know that: a^{-m}=\frac{1}{a^m}

Using this rule:

2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}

So, 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2

Solving:

(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}

So, (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}}

We know that: a^{-m}=\frac{1}{a^m}

\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32

So, \frac{2}{2^{-4}} = 32

3 0
3 years ago
Question is in picture posted but this needs 20 characters so here ya go
Katyanochek1 [597]

Answer:

A

Step-by-step explanation:

The dilation with the center of dilation at the origin and scale factor of 4 has the rule

(x,y)→(4x,4y).

Thus,

  1. A(-1,3)→A'(-4,12)
  2. B(2,1)→B'(8,4)
  3. C(-2,-1)→C'(-8,-4)

A'(-4,12) - option B

B'(8,4) - option C

C'(-8,-4) - option D

3 0
3 years ago
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