A force of 182.6 lb should be applied to lift 700 lb object.
<h3>How to calculate the force?</h3>
Let the force required to lift be F
Total length = 29 in.
Distance of short end from pivot = in.
Distance from long end = 29-6 = 23 in.
Now Equating moments
F × 23 = 700x6
23F = 4200
F = 4200/23
= 182.6 lb
A force of 182.6 lb should be applied to lift 700 lb object.
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Answer:
Is this a scam
Step-by-step explanation:
Answer:
(2, -39)
Step-by-step explanation:
f(x)=-3(x+2)^2+9
f(2)=-3(2+2)^2+9
f(2)=-3(4)^2+9
f(2)=-3(4)(4)+9
f(2)=-3(16)+9
f(2)=-48+9
f(2)=-39
