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3 years ago

How to do this problem

Mathematics

1 answer:

trapecia [35]3 years ago

4 0

You just need to put the smaller numbers on top of the bigger ones in the fractions then multiply them

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Christina and Stacie each determined the cost of printing posters for their campaigns.

Arisa [49]

Answer:

Christina's price per poster is cheaper than Stacie's price per poster.

Step-by-step explanation:

Divide each value

4 0

2 years ago

Is (1, –4) a solution to the equation y = –2x?

givi [52]

Check

-4 = -2(1)

L.H.S

= -2(1)

= -2

is not = R.H.S.

8 0

3 years ago

Read 2 more answers

(2+4+6+....+2006)-(1+3+5+....+2005) the ‘....’ means they add up until it gets to 2006 or 2005. Plz tell me how you get the answ

Naya [18.7K]

I will solve the problem by 2 methods.

<h2>Method 1 to solve:</h2>

I will use Gauss's formula for calculating each string, then we will decrease the results.

We find the number of terms of each string.

$\displaystyle\\n_1=\frac{2006-2}{2}+1=\frac{2004}{2}+1=1002+1=1003~~\text{terms}\\ \\n_2=\frac{2005-1}{2}+1=\frac{2004}{2}+1=1002+1=1003~~\text{terms}\\\\n_1=n_2=n=1003~~\text{terms}\\\\\implies~~~\text{The two strings have the same number of terms.}\\\\S_1 =2+4+6+...+2006=\frac{n(2006+2)}{2}=\frac{1003\times2008}{2}=1003\times1004\\ \\S_2=1+3+5+...+2005=\frac{n(2005+1)}{2}=\frac{1003\times2006}{2}=1003\times1003\\\\S_1-S_2=1003\times1004-1003\times1003=1003(1004-1003)=1003\times1=\boxed{1003}$

<h2>Method 2 to solve:</h2>

We intersect the terms in the second string among the terms of the first string.

$\displaystyle\\S=(2+4+6+....+2006)-(1+3+5+....+2005)=\\\\=2+4+6+....+2006-1-3-5-....-2005=\\\\=2-1+4-3+6-5+...+2006-2005=\\\\=\underbrace{(2-1)+(4-3)+(6-5)+...+(2006-2005)}_{1003~~\text{parenthesis.}}=\\\\\text{We know from the first method that each string has 1003 terms}\\\\=\underbrace{1+1+1+....+1}_{\text{1003 terms equal to 1}} = 1003 \times 1 =\boxed{1003}$

3 0

3 years ago

Students at Salt Lake Community College pay 1.667 * 104 dollars for tuition.Students at George Washington University pay 5.5011

podryga [215]

Answer:

its rigged 1234

Step-by-step explanation:

(2)23x235

5 0

3 years ago

Please answer thank you

Nimfa-mama [501]

Answer:

Yes, (0,4) is a solution

Step-by-step explanation:

We have to plug in 0 in x and 4 in y IN BOTH THE INEQUALITIES.

IF BOTH ARE TRUE, then the system of inequalities is TRUE.

<u>Let's check:</u>

y ≤ -3x+4

4 ≤ -3(0)+4

4 ≤ 4

Is 4 less than OR equal to 4? Yes. THis is satisfied.

<u>Now, checking 2nd one:</u>

y > x^2 + 3x - 2

4 > (0)^2 + 3(0) - 2

4 > -2

Is 4 greater than -2? Yes, it is. So this is satisfied as well.

Hence, (0,4) is a solution to the system of inequalities shown.

3 0

2 years ago

Read 2 more answers

How to do this problem​

How to do this problem