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andrezito [222]
3 years ago
6

Potassium chloride and oxygen gas are formed upon heating potassium

Chemistry
1 answer:
sattari [20]3 years ago
3 0

Answer:

4 mol KClO3

Explanation:

6 mol O2 (2 mol KClO/3 mol O2) =4 mol KClO3

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Calculate the freezing point of a 12.25 m 12.25m aqueous solution of propanol. Freezing point constants can be found in the list
vichka [17]

Answer:

∆t(f) = 49.755C

Explanation:

Freezing point is defined as the point in which a liquid changes from liquid to solid state. Therefore, to calculate the freezing point of aqueous solution of propanol

∆t = k × I × m

Where k is cryscopic constant =

I = vant Hoff factor = 2

M = molar concentration = 12.25m

∆t (f) = 1.9 × 12.25 × 2 = 49.755C

5 0
3 years ago
At the end of an experiment, the product is a mixture of the starting material, which is benzoic acid and the product, which is
Pani-rosa [81]

Answer:

b. Extraction with a solution of sodium hydrogen carbonate, separating the layers, followed by drying and evaporating the organic layer.

Step-by-step explanation:

The ether solution contains your product, benzaldehyde, and some starting material, benzoic acid, the purification steps are:

  1. Extract with a solution of NaHCO₃. The ether layer contains benzaldehyde, and the aqueous layer contains sodium benzoate.
  2. Separate the layers. Keep the ether layer.
  3. Dry the ether solution.
  4. Distill the ether (boiling point 35 °C) and purify the benzaldehyde (178 °C) by steam distillation.

a. is wrong. Extraction with HCl will not remove much of the benzoic acid.

c. is wrong. If you evaporate the organic layer, you will have a mixture of benzaldehyde and benzoic acid.

d. is wrong. If you work with the aqueous layer, you will end up with benzoic acid,

7 0
3 years ago
Calculate the amount of water required to prepare 500g of 2.5% solution of sugar.
Snowcat [4.5K]

(i) We start by calculating the mass of sugar in the solution:

mass of sugar = concentration × solution mass

mass of sugar = 2.5/100 × 500 = 12.5 g  

Then now we can calculate the amount of water:

solution mass = mass of sugar + mass of water

mass of water =  solution mass - mass of sugar

mass of water = 500 - 12.5 = 487.5 g

(ii) We use the following reasoning:

If       500 g solution contains 12.5 g sugar

Then    X g solution contains 75 g sugar

X=(500×75)/12.5 = 3000 g solution

Now to get the amount of solution in liters we use density (we assume that is equal to 1):

Density = mass / volume

Volume = mass / density

Volume = 3000 / 1 = 3000 liters of sugar solution

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