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lbvjy [14]
3 years ago
11

Can someone help me please I’m giving the brainliest

Chemistry
1 answer:
Len [333]3 years ago
3 0
1.more
2.longer
3.warmer
4.northern
5.less
6.shorter
7.colder
8.southern
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A partir de la desintegración del Virreinato del Río de la Plata y durante todo el siglo XXI, los nuevos Estados nacionales que
nalin [4]

Answer:

Verdadero (True).

Explanation:

Después de la desintegración del citado virreinato, los nuevos Estados intentaron establecer sus fronteras, a menudo a través de guerras e invasiones. Cabe destacar la invasión brasileña de Uruguay o la Guerra de la Triple Alianza. En menor medida, lo hicieron a través de tratados internacionales. (After the disolution of the viceroyalship described above, the new States attempted to establish their frontier usually by wars and invasions. It is to highlight the Brazilian invasion of Uruguay or the Triple Alliance' War. In a lesser extent, they made it through international treaties.)

3 0
3 years ago
What is a wind turbine often used for?
kirill115 [55]

Answer:

A

Explanation:

Converting thermal energy into electrical energy

5 0
3 years ago
Read 2 more answers
What is the boiling point elevation constant, Kb, of diethyl ether if 38.2 g of the nonelectrolyte benzophenone, C6H5COC6H5, dis
kakasveta [241]

Answer: the boiling point elevation constant is 1.73^0C/m

Explanation:

Elevation in boiling point is given by:

\Delta T_b=i\times K_b\times m

\Delta T_b=T_b-T_b^0= = Elevation in boling point

i= vant hoff factor = 1 (for non electrolyte)

K_b =boiling point constant = ?

m= molality

\Delta T_b=i\times K_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (diethylether)= 330 g = 0.33 kg

Molar mass of solute (benzophenone)= 182 g/mol

Mass of solute (benzophenone) = 38.2 g

(35.7-34.6)^0C=1\times K_b\times \frac{38.2g}{182g/mol\times 0.33kg}

K_b=1.73^0C/m

Thus the boiling point elevation constant is 1.73^0C/m

3 0
3 years ago
4. How many moles of gold (Au) are in a pure gold nugget having a mass of 25.0 grams.
ikadub [295]
<h3>Answer:</h3>

0.127 mol Au

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 25.0 g Au

[Solve] moles Au

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 25.0 \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})
  2. [DA] Multiply/Divide [Cancel out units:                                                          \displaystyle 0.126923 \ mol \ Au

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.126923 mol Au ≈ 0.127 mol Au

3 0
2 years ago
Read 2 more answers
How many pounds in a 3.00 l bottle of drinking water?
slava [35]

Answer:

             6.61 Pounds

Solution:

Step 1: Calculate Mass of Water as;

                        Density  =  Mass  ÷  Volume

Solving for Mass,

                        Mass  =  Density  ×  Volume   ------ (1)

As,

                        Density of Water  =  1 g.cm⁻³

And,

                        3 L of Water  =  3000 cm³

Putting values in equation 1,

                        Mass  =  1 g.cm⁻³  × 3000 cm³

                        Mass  =  3000 g

Step 2: Convert Grams into Pounds;

As,

                        1 Gram  =  0.002204 Pounds

So,

                        3000 Grams  =  X Pounds

Solving for X,

                      X =  (3000 Grams  ×  0.002204 Pounds)  ÷  1 Gram

                      X =  6.61 Pounds

6 0
3 years ago
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