Homogeneous mixture. (all of the different components of the salad are shown)
Answer:
<h3>The answer is 26.22 g</h3>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
density of iron = 7.874 g/cm³
volume = final volume of water - initial volume of water
volume = 57.65 - 54.32 = 3.33 mL
We have
mass = 7.874 × 3.33 = 26.22042
We have the final answer as
<h3>26.22 g</h3>
Hope this helps you
The molar mass should be 14.898g/mol.
I used the equation 100gx(1/xg/mol)x(1mol/2mol)x(16g/mol+x)/1)=103.7 and solve for x.
I found that equation using stoichiometry and the equation 2m+1/2O2-->m2O
The molar mass of the metal I set to x and the molar mass of the metal oxide is 16+x.
Answer:

Explanation:
<u>1. Rewrite the equation in a more appropriate format for a better understanding: </u>

<u />
<u>2. Multiply the whole equation (both sides) by 84.01 × 52.5 to eliminate the denominators:</u>

<u>3. Do the operations:</u>

<u>4. Add like terms:</u>

<u />
<u>5. Divide both sides by 115.93:</u>

Answer:
The question is incomplete and confusing.
- In the complete ionic equation you write all the ions that are formed. Those are: Pb²⁺, NO₃⁻, K⁺, and I⁻. They all are present in the complete ionic equation.
- In the net ionic equation, the spectator ions do not appear. They are: NO₃⁻ and K⁺. They would not be present in the net ionic equation, but they do in the complete ionic equation.
See below the details.
Explanation:
Which compound will not form ions?
<u />
<u>1. Write the balanced molecular equation:</u>
- Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq)
<u />
<u>2. Write the ionizations for the ionic aqueous compounds:</u>
<u />
- Pb(NO₃)₂(aq) → Pb⁺²(aq) + 2NO₃⁻(aq)
- 2KI(aq) → 2K⁺(aq) + 2I⁻(aq)
- 2KNO₃(aq) → 2K⁺(aq) + 2NO₃⁻(aq)
<u />
<u>3. Write the complete ionic equation:</u>
Pb⁺²(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) → PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)
Hence, since PbI₂(s) does not ionize, but stays in solid form, it will not form ions.
All, Pb⁺², NO₃⁻, K⁺, and I⁻ will be present in the total ionic equation.
It is in the net ionic equation that the spectator ions are removed. Those, are NO₃⁻ and K⁺, because they are on both sides of the complete ionic equation.