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Gekata [30.6K]
3 years ago
13

Pls help What is the range of the function graphed above?!!!!

Mathematics
1 answer:
Flura [38]3 years ago
5 0
I think it’s -infinity
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Complete the Square:<br> 5x^2+16x-40=8<br> (please show your steps)
Sav [38]

Answer:

Step-by-step explanation:

divide through by the coefficient of x^{2}

\frac{5x^{2} }{5} + \frac{16x}{5}  + \frac{-40}{5} = \frac{8}{5}

x^{2} +\frac{16}{5}x  -8 =\frac{8}{5}

x^{2} +\frac{16}{5} x = \frac{8}{5}  +8

x^{2} + \frac{16}{5}  x =\frac{48}{5}

Add half of the square of the coefficient of x  to both sides (\frac{1}{2}  X \frac{16}{5} ) ^{2}

x^{2}  + \frac{16}{5}x + (\frac{1}{2}  X \frac{16}{5} )^{2} = \frac{48}{5} +(\frac{1}{2} X \frac{16}{5} )^{2}

x^{2}  +\frac{16}{5} x +(\frac{16}{10}) ^{2} =\frac{48}{5} +\frac{64}{25}

(x +\frac{16}{10})^{2}    =\frac{304}{25}

x +\frac{16}{10} =±\sqrt{\frac{304}{25} }

x = -\frac{16}{10} ± \sqrt{\frac{304}{25} }

x=-\frac{16}{10}  + \sqrt{\frac{304}{25} } or-\frac{16}{10}  - \sqrt{\frac{304}{25} }

x = 1.89 or -5.09

5 0
3 years ago
Which relation is a function? A) y2 + 3x = 9 B) y(2x + 4y) = 8 C) x2 + 7x = 7y2 D) yx = x3 + 4x2 + 4x
Maslowich
The first one is a parabola opening sideways so it will not pass the vertical line test
B   not a function as it can be arranged in form  x =  expression in y^2 so it would be a one-to-many relation.

D is a function  because its a parabola which open upwards so it will pass the vertical line test
6 0
3 years ago
Hi how are you today?
Gemiola [76]
I’m ok lots of school work
8 0
3 years ago
Read 2 more answers
What is -4 = k - (-6) ? ​
antoniya [11.8K]

Answer: k = -10

Step-by-step explanation:

-4 = k + 6

-4 - 6 = k

-10 = k

7 0
3 years ago
Read 2 more answers
PLEASE HELP ITS DUE TODAY AND THIS IS MY LAST QUESTION
exis [7]

Answer:

Left: The substance is decreasing by 1/2 every 12 years

Right: The substance is decreasing by 5.61% each year

Step-by-step explanation:

exponential decay

A = P(1-r)ᵇⁿ, where A is the final amount, P is the initial amount, r is the rate decreased each time period, b is the number of years, and n is the number of times compounded each year

let's write each formula in terms of this

left:

f(t) = 600(1/2)^(t/12)

matching values up...

A = P(1-r)ᵇⁿ

A = f(t)

P = 600

1 - r = 1/2 -> r = 1/2

t/12 = bn -> b = number of years = t, so bn = b/12 -> n = 1/12. Thus, it is compounded 1/12 times each year, so it is compounded every t*12 = 12 years. If it was compounded each month, it would be compounded 12 times a year

Thus, this is decreasing by a rate of 1/2 each 12 years

right:

f(t) = 600(1-0.0561)^(t)

matching values up...

A = P(1-r)ᵇⁿ

A = f(t)

P = 600

1 - r = 1 - 0.0561 -> r = 0.0561 = 5.61%

t = bn -> b = number of years = t, so bn = b -> n = 1. Thus, it is compounded annually (1 time each year)

Thus, this is decreasing by a rate of 5.61% each year

8 0
2 years ago
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