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professor190 [17]
3 years ago
13

Control activities are performed within processes (e.g., segregation of duties required in processing cash receipt transactions)

and over the technology environment. a. True b. False
Chemistry
1 answer:
galina1969 [7]3 years ago
6 0

Answer:

a. True

Explanation:

The control objectives seek to support the fulfillment of the critical factors of business success, in order to finally support the achievement of the institutional objectives, on this the CITI is based

It is very important to clearly identify the relationships of the control objectives with other internal control elements such as:

 · Critical success factors receive direct support from control objectives to support compliance.

· The control objectives are made up of control goals, which allow them to have a more detailed perspective of the control objectives and at the same time facilitate the evaluation of their compliance.

CITI CONCEPT:

It is the set of administration elements that a company establishes in a coordinated way so that the use of information technology resources effectively supports the institutional objectives of the company

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The number of possible different orbital shapes for the third energy level is
adelina 88 [10]

Answer:

option c) 3 is the correct option

Explanation

as we  know that 3rd principal energy level contains 3 sub levels,which are named as s,p and d. These sub levels further contain different numbers of orbitals,

and these sub levels can be termed as  regions of probability of finding an electron, and each orbital may have a maximum number of two electrons in it.

8 0
3 years ago
Read 2 more answers
What is the density of an object having a mass of 5.0 g and a volume of 45.0 cm3?
shutvik [7]
D = m / V

d = 5.0 / 45.0

d = 0.111 g/cm³
7 0
3 years ago
Read 2 more answers
A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at
Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

3 0
3 years ago
What equipment is needed to weigh 5.0 grams of zinc?
otez555 [7]
You would weigh the zinc with a weight, Zinc is a mineral so wether it's a solid or a liquid you would measure it with a zinc.
5 0
2 years ago
What volume would 56.2 mL of gas at 820 mm of Hg occupy at 720 mm of Hg?
Andreyy89

Answer:

49.35  mL

Explanation:

Given: 56.2 mL of gas

To find: volume that 56.2 mL of gas at 820 mm of Hg would occupy at 720 mm of Hg

Solution:

At 820 mm of Hg, volume of gas is 56.2 mL

At 1 mm of Hg, volume of gas is \frac{56.2}{820}

At 720 mm of Hg, volume of gas is \frac{56.2}{820}(720)=49.35\,\,mL

3 0
3 years ago
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