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rewona [7]
3 years ago
12

Which condition is a neuron in when the outside of the neuron has a net positive charge and the inside has a net negative charge

?. Threshold. Action potential . Resting potential
Physics
2 answers:
White raven [17]3 years ago
8 0
The condition is a neuron in when the outside of the neuron has a net positive charge and the inside has a net negative charge (due to accumulation of more sodium ions) is C. resting potential. T<span>he </span>resting membrane<span> </span>potential<span> of a </span>neuron<span> is approximately -70 mV (mV=</span><span>millivolt)</span>
kotegsom [21]3 years ago
5 0

Answer:

Resting potential

Explanation:

As we know that all the charges are stored inside and outside the neuron in form of positive and negative charge on inner and outer surface.

These charges are stored and remains at rest on the inner and outer surface due to there mutual electric field.

So here the energy must be in the form of electrostatic potential energy where charge is in stationary condition.

So Neuron in this case will hold this charge and hence it will store this electrostatic energy in it due to this stationary charge distribution.

So here the correct answer will be

RESTING POTENTIAL

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Fat Albert (the TV show character) runs up the stairs on Monday. On Tuesday, he walks up the same set of stairs. Which day did h
lys-0071 [83]

Answer:

Tuesday bc instead of running he/she was walking bc he/she might not have as much energy

Explanation:

8 0
3 years ago
A man stands by a train track to watch the train car go by. Inside, a man walks through the train car eating a hot dog (the hot
antiseptic1488 [7]

Answer:

D) 11 m/s

Explanation:

The problem asks us to calculate the velocity of the hot dog with respect to the observer stationary outside the train. This velocity is given by:

v=v_t + v_m + v_h

where

v_t=+10 m/s is the velocity of the train (towards right)

v_m=+2 m/s is the velocity of the man (towards right)

v_h=-1 m/s is the velocity of the hot-dog (towards left, so we put a negative sign)

Substituting the numbers into the equation, we find

v=+10 m/s+2 m/s-1 m/s=+11 m/s

and the positive sign means the velocity is toward right.

5 0
3 years ago
Read 2 more answers
Example of first, second and third law of motion.​
statuscvo [17]

Examples of Newton's three law of motion.

First law of motion: A rocket being launched up in the atmosphere.

Second law of motion:while riding a bicycle, a bicycle acts as a mass and our legs pushing on the pedals of the bicycle is the force.

Third law of motion:when we jump off from the boat,the boat moves backward.

Hope,it will helpyouu!

4 0
2 years ago
A 2.5-kg ball and a 5.0-kg ball have an elastic collision. Before the collision, the 2.5-kg ball was at rest and the other ball
lesantik [10]

The kinetic energy of 2.5 kg ball after collision is 27.09 J.

Answer:

Explanation:

In elastic collision, the sum of momentum of the objects before collision will be equal to the sum of momentum of the objects after collision.  

We know that momentum is the product of mass and velocity acting on any object.

So, the conservation of energy in elastic collision leads to following equation:

M_{1} u_{1} +M_{2} u_{2}=M_{1}  v_{1}+M_{2}  v_{2}

Since, the momentum is conserved ,the kinetic energy will also be conserved in elastic collision. So

M_{1} u_{1} ^{2}+M_{2} u_{2} ^{2}=M_{1}v_{1} ^{2}+  M_{2}v_{2} ^{2}

Since initial velocity for M1 ball is zero, then

M_{2} u_{2}=M_{1}  v_{1}+M_{2}  v_{2}

and

M_{2} u_{2} ^{2}=M_{1}v_{1} ^{2}+  M_{2}v_{2} ^{2}

So, on solving all the above equation, we get an equation for velocity and that is

\frac{2M_{2}u_{2} }{(M_{1}+M_{2}  }=final velocity of ball with mass 2.5 kg

v = \frac{2(5*3.5)}{2.5+5}=4.67 m/s

So kinetic energy will be 1/2 mv2

Kinetic energy of 2.5 kg ball is \frac{1}{2}*2.5*(4.67)^{2}  =27.09 J

So the kinetic energy of 2.5 kg ball after collision is 27.09 J.

6 0
3 years ago
I'm not sure what equation to use.
Lelechka [254]
I would think that you would multiply then divide
7 0
4 years ago
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