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avanturin [10]
3 years ago
15

What is the frequency of a wave if 3 crests pass in 6 seconds?

Physics
2 answers:
AlexFokin [52]3 years ago
8 0
A. 0.5 hz because frequency os the amount of waves that pass per one second.
zavuch27 [327]3 years ago
6 0

Answer:

b. 2Hz

Explanation:

Frequency is defined as the number of wavelengths passing a particular point per second.

If 3 crests pass a point in two seconds, then we know that 6 crests pass the point per second.

Therefore 2 wavelengths pass the point per second, and hence the frequency of the wave is 2Hz.

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Which of the following energy resources produces greenhouse gases?
Blizzard [7]
Coal is burned to get energy. By burning coal, green houses gases like carbon dioxide, nitrogen oxides and suphur oxides are produced.

Rest of the energy sources given in the option are clean energies.

Answer is A.
4 0
3 years ago
You rub a clear plastic pen with wool, and observe that a strip of invisible tape is attacted to the pen. Assuming that the pen
gayaneshka [121]

Answer:

option B

Explanation:

When you rub a clear plastic pen with the wool the plastic pen gets charges this phenomenon is known as frictional charging.

Due to rubbing, the pen gets negatively charged.

We know, opposite charge attract each other and the same charge repel each other.

So, when the pen is negatively charged the tape might be positively charged or the tape might be uncharged.

Hence, the correct answer is option B

6 0
3 years ago
A +12 μC charge and -8 μC charge are 4 cm apart. Find the magnitude and direction of the E-field at the point midway between t
Natasha_Volkova [10]

Answer:

Explanation:

Given

Charge of first Particle q_1=+12\ \mu C

Charge of second Particle q_2=-8\ \mu C

distance between them d=4\ cm

k=9\times 10^{9}

magnetic field due to first charge at mid-way between two charged particles is

E_1=\frac{kq_1}{r^2}

r=\frac{d}{2}=\frac{4}{2}=2\ cm

E_1=\frac{9\times 10^9\times 12\times 10^{-6}}{(2\times 10^{-2})^2}

E_1=27\times 10^7\ N/C (away from it)

Electric field due to q_2=-8\ \mu C

E_2=\frac{kq_2}{r^2}

E_2=-\frac{9\times 10^9\times 8\times 10^{-6}}{(2\times 10^{-2})^2}

E_2=-18\times 10^7\ N/C(towards it)

E_{net}=E_1+E_2

E_{net}=9\times 10^7\ N/C(away from first charge)        

8 0
3 years ago
Mass m, moving at speed 2v, approaches mass 4m, moving at speed v. The two collide elastically head-on. Part A Find the subseque
meriva
Thank you for posting your question here at brainly. A mass of m moves with 2V towards in the opposite direction of a mass, 4m moving at a speed of V, the speed of m was 2/5V and the mass of 4m was 7.5V. I hope it helps.
4 0
3 years ago
Read 2 more answers
A man does 500 j work pushing a car a distance of 2m how much force does he apply
olasank [31]

Answer: 250 N

Explanation:

Use equation for work

W=F*d

d=2m

W=500J

F=?

-----------------------

W=Fd

F=W/d

F=500J/2m

F=250N

6 0
3 years ago
Read 2 more answers
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