<span>x^2 + 8x = -3
</span><span>x^2 + 8x + 16 = -3 + 16
using a^2 + 2 a b + b^2 = (a+b)^2
</span><span>
</span>x^2 + 8x + 16 = 13
<span>(x +4)^2 = 13
answer : 16 is the number </span><span>you must add to complete the square</span>
Answer: no not less than 23
Answer:
Not a solution.
Step-by-step explanation:
(x, y)
(-1, 2)
Substitute the x and y values in the expression with the point given.
8x + y > -6
8(-1) + 2 > -6
-8 + 2 > -6
-6 > -6
Since our final value has to be greater than -6 but is instead equal to -6, the solution is not true.
I see your last line is : c(x) = 0.9(x^2-10)^2 + 101.1
Let y = x^2, then c(y) = 0.9(y-10)^2 + 101.1
Apparently, c(y) is a parabola, min is 101.1 when y = 10, max is infinity
So let x^2 = 10 -> x = sqrt(10) or -sqrt(10), min is 101.1, max is infinity
Answer:
sorry just came here for the points
Step-by-step explanation:
