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densk [106]
4 years ago
15

How much percent of earth is water

Chemistry
1 answer:
horsena [70]4 years ago
6 0

71% of the earth is water and the 29% is continents and islands.

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Is cotton opaque or not
qaws [65]
Cotton is opaque.  Opaque objects do not let light pass through.  You can't see through the objects that are opaque.
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3 years ago
g The following equation is given for the dissociation of the complex ion Ag(NH3) 2. The dissociation constant, Kd, is the equil
Sveta_85 [38]

Answer:

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

Explanation:

Let's consider the dissociation reaction of the complex ion Ag(NH₃)₂⁺.

Ag(NH₃)₂⁺(aq) ⇄ Ag⁺(aq) + 2 NH₃(aq)

The dissociation constant, Kd, is the equilibrium constant for the dissociation of the complex ion, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.

The dissociation constant for this reaction is:

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

8 0
3 years ago
This section of the periodic table is called a(n)
Mice21 [21]

Answer:

Is it <u>Group</u>?

Explanation:

6 0
3 years ago
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Help on my hw please
Reika [66]

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8 0
4 years ago
What is the osmolarity of .00001 grams (0.1 mg%) of ethanol (does not dissociate) in one liter?
MrMuchimi

Explanation:

As it is known that non-electrolytes do not dissociate. Therefore, molarity of such a solution is equal to the osmolarity of solution.

As, molar mass of ethanol = 46.07 g/mol

Therefore, no. of moles of ethanol will be calculated as follows.

               No. of moles = \frac{mass}{\text{molar mass}}

                                     = \frac{0.00001 g}{46.07 g/mol}

                                     = 2.17 \times 10^{-7} mol

As, molarity is moles of solute in liter of solution. Hence, molarity of ethanol is as follows.

                           Molarity = \frac{\text{no. of moles}}{volume}

                                          = \frac{2.17 \times 10^{-7} mol}{1 L}

                                          = 2.17 \times 10^{-7} mol/L

Since, for the given solution Molarity = osmolarity

Thus, we can conclude that osmolarity of .00001 grams (0.1 mg%) of ethanol  in 1 L is 2.17 \times 10^{-7} osmol/L.

8 0
3 years ago
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