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FinnZ [79.3K]
3 years ago
13

Which situation is appropriate for using rate laws?

Chemistry
2 answers:
alukav5142 [94]3 years ago
8 0
The answer is: To see how fast hydrogen peroxide decomposes into water and oxygen.
Hope I helped god bless U ;)
Nastasia [14]3 years ago
3 0

Answer:

to see how fast hydrogen peroxide decomposes into water and oxygen

Explanation:

Let’s consider a chemical reaction,

A -> B  

Rate law is given by the equation:

r = k [A]

where r is the rate of a reaction, k is the rate constant and [A] is the molar concentration of the reactant A.  The rate of the reaction, r measures how fast the reactant gets converted to products.  

Therefore, the rate of the reaction will indicate how fast hydrogen peroxide decomposes into water and oxygen.

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If .75 moles of ammonia is needed, how many grams of nitrogen will be consumed?
MrMuchimi

We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.

The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.

Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-

N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)

According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, \frac{1 X 0.75}{2} moles = 0.375 moles of nitrogen is required.

Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.

Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.


5 0
3 years ago
A _ is a whole number that appears before formula in an equation
Marina CMI [18]
A coefficient is a whole number that appears before the formula in an equation.
7 0
3 years ago
Is this chemical equation balanced?
cluponka [151]

Answer:

Yes

Explanation:

5 0
3 years ago
Read 2 more answers
How much heat does it take to turn water from -30 degreesC to 120 degreesC?
natka813 [3]

Answer:

110 degrees C

Explanation:

4 0
2 years ago
Read 2 more answers
An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?
umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

K_b = molal boiling point elevation constant = 0.51°C/m

m_{solute} = Given mass of solute (CsCl) = 8.00 g

M_{solute} = Molar mass of solute (CsCl) = 168.4  g/mol

W_{solvent} = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC

Hence, the boiling point of solution is 100.53

6 0
3 years ago
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