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3 years ago

State the colour of a solution of copper sulphate

Chemistry

1 answer:

dybincka [34]3 years ago

5 0

The colour of copper sulphate solution is blue

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1 loop in the primary coil and 8 loops in the secondary. If the secondary voltage is 120 V, what must be the primary voltage

Jet001 [13]

Answer:

$V_{p} = 15 V$

Explanation:

<u>Given the following data;</u>

Number of loops in primary coil, Np = 1 loop.

Number of loops in secondary coil, Ns = 8 loops

Voltage in secondary coil, Vs = 120V

To find the voltage in the primary coil, Vp;

Transformer ratio is given by the formula;

$\frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}}$

Making Vp the subject of formula;

$V_{p} = \frac{N_{p}}{N_{s}} * V_{s}$

Substituting into the equation, we have;

$V_{p} = \frac{1}{8} * 120$

$V_{p} = \frac{120}{8}$

$V_{p} = 15 V$

Therefore, the voltage in the primary coil, Vp is 15 Volts.

4 0

3 years ago

8. Why would it be a bad idea to make coins made of sodium metal?

Elina [12.6K]

Answer:

Sodium reacts with the oxygen in air. It reacts vigorously with oxygen and the moisture that is already present in the air and thus catches fire.

5 0

3 years ago

How many valence electrons are there in an argon atom?

dalvyx [7]

Answer:

The element argon is in column 8A and is a noble gas. Nobles gases are completely stable because their outershell is filled with all eight electrons. Argon has eight valence electrons.

4 0

2 years ago

3. A 31.2-g piece of silver (s = 0.237 J/(g · °C)), initially at 277.2°C, is added to 185.8 g of a liquid, initially at 24.4°C,

VARVARA [1.3K]

Answer:

$Cp_{liquid}=2.54\frac{J}{g\°C}$

Explanation:

Hello,

In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

$Q_{Ag}=-Q_{liquid}$

That in terms of the heat capacities, masses and temperature changes turns out:

$m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})$

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

$Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}$

Best regards.

6 0

4 years ago

Who likes pomegranates

Sergio [31]

Answer:

I LIKE POMEGRANATES

Explanation

A LOT

8 0

3 years ago