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Ganezh [65]
3 years ago
8

Which factors control the cooling time of magma within the crust?

Physics
2 answers:
Oxana [17]3 years ago
8 0

Answer:

The depth of the intrusion,

the shape and size of a magma body

Explanation:

The depth of the intrusion, the shape and size of a magma body: the greater the surface area for a given volume of intrusion, the faster it cools, and the presence of circulating ground water: water passing through magma absorbs and carries away heat

Tatiana [17]3 years ago
4 0

Answer:

• Depth of the intrusion.

• The shape and size of the magma body

• Presence of groundwater

Explanation:

The depth of the intrusion, the shape and size of a magma body: the greater the surface area for a given volume of intrusion, the faster it cools, and the presence of circulating ground water: water passing through magma absorbs and carries away heat.

As the rate of cooling increases, crystal size decreases. This means that something which cools very quickly will have smaller crystal formations, and something which cools slowly will have larger crystal formations. This is easily seen in igneous rock, which may cool at variable rates.

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a rugby player tackles another player. in terms of kinetic energy and work done, why is it more difficult to tackle a heavier pl
matrenka [14]
The weight of the heavier player bakes it a lot harder to push him or do work because of the net force gravity<span />
6 0
3 years ago
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The internal energy of nmoles of an ideal gas depends on a. one state variable T.
VMariaS [17]

Answer:

Correct option a. one state variable T.

Explanation:

In the case of an ideal gas it is shown that internal energy depends exclusively on temperature, since in an ideal gas any interaction between the molecules or atoms that constitute it is neglected, so that internal energy is only kinetic energy, which depends Only of the temperature. This fact is known as Joule's law.

The internal energy variation of an ideal gas (monoatomic or diatomic) between two states A and B is calculated by the expression:

ΔUAB = n × Cv × (TB - TA)

Where n is the number of moles and Cv the molar heat capacity at constant volume. Temperatures must be expressed in Kelvin.

An ideal gas will suffer the same variation in internal energy (ΔUAB) as long as its initial temperature is TA and its final temperature TB, according to Joule's Law, whatever the type of process performed.

3 0
3 years ago
Help yea I need help
swat32
Answer is D I think....
8 0
3 years ago
1. Determine the energy released per kilogram of fuel used.
yarga [219]

200 MeV of energy  
E1/E2=7.61=8

U is equal to 1 kilogram or 1000 g.
There are 6.02310 23 atoms in one mole, or 235 g, of uranium. Therefore, 6.02310 23 atoms are present in 1000 g of 92/235 U.
It is understood that one atom releases 200 MeV of energy during its fission.

As a result, the energy released from the fission of one kilogram of 92/235 is given by E 2 = 6.02310 23 1000200/235 =5.10610 26 MeV E1/E2=7.61=8

In light of this, the energy released during the fusion of one kilogram of hydrogen is roughly eight times greater than the energy generated during the fission of one kilogram of uranium.

To learn more about Fission please visit -
brainly.com/question/27923750
#SPJ1

6 0
2 years ago
A 2kg object is dropped from a height 10m.Calculate the speed of the object after it has fallen 5m, assuming there is no resista
Ugo [173]

Answer:

10m/s

Explanation:

d=v_ot+\dfrac{1}{2}at^2

Since there is no initial velocity as the object is dropped, you can write the following equation:

5=\dfrac{1}{2}(10)t^2 \\\\1=t^2 \\\\t=1

Now that you know how long the fall took, you can use another physics equation to find the velocity at that point.

v_f=v_o+at

Since there once again is no initial velocity, you can rewrite this as:

v_f=at=(10)(1)=10m/s

Hope this helps!

5 0
4 years ago
Read 2 more answers
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