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Fudgin [204]
3 years ago
8

As you are trying to move a heavy box of mass m, you realize that it is too heavy for you to lift by yourself.There is no one ar

ound to help, so you attach an ideal pulley tothe box and a massless rope to the ceiling, which you wrap aroundthe pulley. You pull up on the rope to lift the box. Use g or themagnitude of the acceleration due to gravity and neglect frictionforces.
Part A What is the magnitude F of the upward force you must apply to the ropeto start raising the box with constant velocity?

Physics
1 answer:
Ira Lisetskai [31]3 years ago
5 0

Answer: magnitude of applied force is FA = mg + F

Where F is the resultant force downward that the rope moves with

Explanation:

Force downwards F is,

F = FA - T

T is the upwards tension force on the rope

FA is the actual applied force in pulling the rope down.

Therefore, T = FA - F .....equ. (1)

For the box to move up with force ma ( it's mass times its acceleration upwards) upwards tension on the roap must exceed its own weight mg ( it's mass times acceleration due to gravity 9.8m/s^2)

Therefore, ma = T - mg

T = ma + mg ..... equ. (2)

Equating equ. 1 and 2

T = FA - F = ma + mg

Therefore FA = ma + mg + F

But at constant velocity a = 0

Magnitude of applied force becomes

FA = mg + F

See image below

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Answer:

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an object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m. determine the image height (in cm)
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Given :

An object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m.

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a lump of putty and a rubber ball have equal mass. both are thrown with equal speed against a wall. the putty sticks to the wall
RUDIKE [14]
The bouncy ball experiences the greater momentum change.

To understand why, you need to remember that momentum is actually
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The putty and the ball have the same mass, and you throw them
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Answer:

The correct options are;

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