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3 years ago

8

Protons have a positive charge A.True B.False

2 answers:

PIT_PIT [208]3 years ago

5 0

Answer:

TRUE

Explanation:

Protons have a positive charge. Electrons have a negative charge. The charge on the proton and electron are exactly the same size but opposite. Neutrons have no charge.

hram777 [196]3 years ago

4 0

Answer:

The answer is A) True. See the explanation below, please

Explanation:

A positively charged subatomic particle within the atomic nucleus is called a proton. The number of protons is given by the atomic number of an element (which is displayed in the periodic table).

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You happen to know that the coefficient of static friction between your patio table and the ground is 0.42. You decide you want

Deffense [45]

Answer:

If the force applied is larger than 185.2 N, yes.

Explanation:

In order to move the table, the pushing force must be larger than the frictional force. The frictional force is given by:

$F_f = \mu mg$

where

$\mu=0.42$ is the coefficient of static friction

$m=45 kg$ is the mass of the table

$g=9.8 m/s^2$ is the gravitational acceleration

Substituting,

$F_f=(0.42)(45 kg)(9.8 m/s^2)=185.2 N$

So, we are able to move the table if we push with a force larger than 185.2 N.

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3 years ago

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MaRussiya [10]

The answer is B. Breaking down of rocks.

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3 years ago

How can understanding velocity help to prevent a mid-air collision

dsp73

Answer:

To maintain enough time to prevent a collision, a system operating in air traffic where aircraft speed does not

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3 years ago

What is the importance of measurement? <br>

Kruka [31]

Answer:

To know the time ,length area

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3 years ago

34. A train, starting from rest, accelerates along the platform at a uniform rate of 0.6 m/s2. A passenger standing on the platf

ira [324]

Answer:

4.08 s

Explanation:

Let the passenger took "t" time to catch the train

so in this case the total distance moved by the train + 5 m = total distance moved by the passenger

so we will have

distance moved by train is given as

$d_1 = \frac{1}{2}(0.6) t^2$

also the distance moved by passenger

$d_2 = \frac{1}{2}(1.2) t^2$

so we will have

$d_1 + 5 = d_2$

$0.3 t^2 + 5 = 0.6 t^2$

$0.3 t^2 = 5$

t = 4.08 s

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3 years ago