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3 years ago

Protons have a positive charge A.True B.False

Physics

2 answers:

PIT_PIT [208]3 years ago

5 0

Answer:

TRUE

Explanation:

Protons have a positive charge. Electrons have a negative charge. The charge on the proton and electron are exactly the same size but opposite. Neutrons have no charge.

hram777 [196]3 years ago

4 0

Answer:

The answer is A) True. See the explanation below, please

Explanation:

A positively charged subatomic particle within the atomic nucleus is called a proton. The number of protons is given by the atomic number of an element (which is displayed in the periodic table).

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You use a slingshot to launch a potato horizontally from the edge of a cliff with speed v0. The acceleration due to gravity is g

sergij07 [2.7K]

Answer:

t = 2 v₀ / g

Explanation:

For this projectile launch exercise we use the displacement equations

x = vox t

y = y₀ + $v_{oy}$ t - ½ g t²

As it is launched horizontally the vertical velocity is zero and the point of origin of the coordinate system is here, so y₀ is zero.

x = v₀ t

y = ½ g t²

They ask us for the time for which

x = y

vo t = ½ g t²

t = 2 v₀ / g

8 0

2 years ago

Years ago, a block of ice with a mass of about 20.0 kg was used daily in a home icebox. The temperature of the ice was 0.0°C whe

m_a_m_a [10]

Answer: The ice absorb 6671.1 kJ of thermal energy.

Explanation:

The conversions involved in this process are :

$0.00^0C=273K$

$:H_2O(s)(273K)\rightarrow H_2O(l)(273K)$

Now we have to calculate the enthalpy change.

$\Delta H=n\times \Delta H_{fusion}$

where,

$\Delta H$ = enthalpy change = ?

m = mass of ice = 20.0 kg = $20.0\times 10^3g$ (1kg=1000g)

n = number of moles of ice= $\frac{\text{Mass of ice}}{\text{Molar mass of water}}=\frac{20.0\times 10^3g}{18g/mole}=1.11\times 10^3mole$

$\Delta H_{fusion}$ = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

Now put all the given values in the above expression, we get

$\Delta H=1.11\times 10^3mole\times 6010J/mole$

$\Delta H=6671100J=6671.1kJ$ (1 kJ = 1000 J)

Therefore, the enthalpy change is, 6671.1 kJ

6 0

3 years ago

The plates of a parallel-plate capacitor are 700 cm2 in area and 0.3 cm apart. The potential difference between the plates is 93

Kisachek [45]

Answer: a) E = 311,666.7 V/m, b) q = 1.54×10^-10c, c) F = 4.799×10^-5 N, d) 0.0629 J

Explanation:

Area = 700cm² = (700/100)² = 7² = 49m²

Distance between plates (d) = 0.3cm = 0.3/100 = 0.003 m

V = potential difference = 935v

Recall that for a capacitor that V = Ed

Where E = strength of electric field.

935 = E× 0.003

E = 935/ 0.003

E = 311,666.7 V/m

C =qV

Where q = magnitude of charge on capacitor.

We need to get the value for C before we can get for q.

C =ε0×A/d

Where ε0 =permittivity of free space = 8.85×10^-12

Hence we have that

C = 8.85×10^-12 × 49/ 0.003

C = 4.32×10^-10/0.003

C = 1.44×10^-7 F

But C=qV

1.44×10^-7 = q (935)

q = 1.54×10^-10c

F=Eq

Where E = strength of electric field = 311,666.7 V/m, q = 1.54×10^-10c

F = 311,666.7 × 1.54×10^-10

F = 4.799×10^-5 N

Total energy stored = cv²/2

Total energy = 1.44×10^-7 × 935²/2

Total energy = 0.0629 J

4 0

2 years ago

What do I round to for the last question

Julli [10]

Answer:

V{+7 + 1000

Explanation:

Because Y + 7 + (828 and Y X P + ()

6 0

2 years ago

Móvil A : V = 16 m/s ; t = 5 sMóvil B : V = 15 m/s ; t = 6 s Móvil C : V = 24 m/s ; t = 3 s Calcular la distancia que recorre ca

patriot [66]

Answer:

dC = 72m < dA = 80m < dB = 90m

Explanation:

In order to calculate the distance traveled by each mobile, you use the following formula:

$d=vt$ (1)

d: distance traveled

v: speed of the car

t: time of the motion

You replace the values of v and t for each mobile:

mobile A:

$d_A=v_At_A=(16m/s)(5s)=80m$

mobile B:

$d_B=v_Bt_B=(15m/s)(6s)=90m$

mobile C:

$d_C=v_Ct_C=(24m/s)(3s)=72m$

Then, you obtain that he distances traveled by the mobiles show:

dC = 72m < dA = 80m < dB = 90m

4 0

2 years ago