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GREYUIT [131]
4 years ago
15

Convert 2.17 x 10 -8 Mg into pg

Chemistry
1 answer:
viktelen [127]4 years ago
4 0
This answer is 24 because 2.17 x 10 -8 is 24 so that would be your answer
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makkiz [27]
The atomic density cuases them to be different u can measure the weight mass density # 28 was cut off picture by the way
7 0
3 years ago
PLEASEE HELPP ME WITH THIS QUESTION I REALLY NEED A GOOD EXPLANATION AND BE SPECIFIC PLEASE WILL MARK BRAINIEST FOR CORRECT ANSW
Mice21 [21]

Answer:

The three parts of the seed are the embryo, endosperm and the seed coat.

Explanation:

The embryo is the young multicellular organism before it emerges from the seed. The endosperm is a source of stored food which consists mostly of starches. The seed coat consists of one or more protective layers that encase the seed.

Hope this helps x

4 0
3 years ago
What is the volume of 0.200 mol of an ideal gas at 200. kPa and 400. K?
viva [34]

The ideal gas under STP is 22.4 L/mol. While the gas has a rule of P1V1/T1=P2V2/T2. So the volume under 101 kPa and 273 K is 0.2*22.4=4.48 L.


4 0
3 years ago
Read 2 more answers
For the reaction A+B↽−−⇀C+D, assume that the standard change in free energy has a positive value. Changing the conditions of the
77julia77 [94]

Explanation:

a. Adding a catalyst

no effect .( Catalyst can only change the activation energy but not the free energy).

b. increasing [C] and [D]

Increase the free energy .

c. Coupling with ATP hydrolysis

decrease the free energy value .

d.Increasing [A] and [B]

decrease the free energy.

7 0
3 years ago
The density of pure gold is 19.3g/cm3. What is the volume of 1.00 g of pure gold?
soldier1979 [14.2K]

Answer: Volume of 1g of pure gold v=0.05181 \mathrm{cm}^{3}

Given;

Density of a pure gold=19.3 g / c m^{3}

Mass of a pure gold =1g

To find:

Volume of 1g of pure gold

Solution:

According to the formula,

Density= Mass/Volume

     \rho=m / v

Where \rho=density of pure gold

           m=mass of pure gold

          v=volume of pure gold

From the above equation volume can be calculated as

v=m / \rho

Substitute the values of mass and density value in the above equation

v=1 / 19.3

v=0.05181 \mathrm{cm}^{3}

Result:

Thus the volume of 1g of pure gold is v=0.05181 \mathrm{cm}^{3}

8 0
3 years ago
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