Question

A gas mixture contains 88 grams of oxygen gas, 88 grams of nitrogen gas, and 12 grams of nitrogen dioxide gas,

Answer 1

BROO DEE YOU ALREADY KNOW WHAT IS STOP DA CAP, o.81

Answer 2

88 g O2 x 1 mol O2/32 g = 2.75 moles O2
88 g N2 x 1 mol N2/28 g = 3.14moles N2
12 g NO2 x 1 mol NO2/46 g = 0.261 moles NO2
TOTAL moles = 6.15 moles
mole fraction N2 = 3.14/6.15 = 0.51