A gas mixture contains 88 grams of oxygen gas, 88 grams of nitrogen gas, and 12 grams of nitrogen dioxide gas,
2 answers:
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Answer : The values of are
respectively.
Explanation :
The given balanced chemical reaction is,
First we have to calculate the enthalpy of reaction .
where,
= enthalpy of reaction = ?
n = number of moles
= standard enthalpy of formation of gaseous benzene = 82.93 kJ/mol
= standard enthalpy of formation of liquid benzene = 49.04 kJ/mol
Now put all the given values in this expression, we get:
Now we have to calculate the entropy of reaction .
where,
= entropy of reaction = ?
n = number of moles
= standard entropy of formation of gaseous benzene = 269.2 J/K.mol
= standard entropy of formation of liquid benzene = 173.26 J/K.mol
Now put all the given values in this expression, we get:
Now we have to calculate the Gibbs free energy of reaction .
As we know that,
At room temperature, the temperature is .
Therefore, the values of are
respectively.