Question

Solve the inequality.

Answer 1

Answer:

$x \leqslant - 3$

option C is the right option.

Solution,

$\frac{x}{3} - \frac{x - 1}{2} \geqslant 1 \\ = \frac{2x - 3( x - 1)}{6} \geqslant 1 \\ = \frac{2x - 3x + 3}{6} \times 6 \geqslant 6 \\ = 2x - 3x + 3 \geqslant 6 \\ = - x + 3 \geqslant 6 \\ = - x + 3 - 3 \geqslant 6 - 3 \\ = - x \geqslant 3 \\ = - ( - x) \leqslant - 3 \\ = x \leqslant - 3$

hope this helps...

Good luck on your assignment

Answer 2

Answer:

Let's solve your inequality step-by-step.

$\frac{x}{3}-(\frac{x-1}{2})\geq1$

Step 1: Simplify both sides of the inequality.

$\frac{-1}{6}x+\frac{1}{2}\geq1$

Step 2: Subtract 1/2 from both sides.

$\frac{-1}{6}x+\frac{1}{2}-\frac{1}{2}\geq1-\frac{1}{2}$

$\frac{-1}{6}x\geq\frac{1}{2}$

Step 3: Multiply both sides by 6/(-1).

$(\frac{6}{-1})*(\frac{-1}{6}x)\geq(\frac{6}{-1})*(\frac{1}{2})$

$x\leq-3$

Answer:

$x\leq-3$ This is the answer

I hope this help you :)