Answer:
Hello your question is incomplete attached below is the complete question
answer: wt.% of alloy that is solid = 61.5%
wt.% of allot that is liquid = 38.5%
Explanation:
To determine the wt.% of the alloy that is solid
= 
= 
= 61.5%
To determine the wt.% of the alloy that is liquid
= 
= 
= 38.5%
attached below is a free hand sketch as well
Answer:
The rate of work output = -396.17 kJ/s
Explanation:
Here we have the given parameters
Initial temperature, T₁ = 355°C = 628.15 K
Initial pressure, P₁ = 350 kPa
h₁ = 763.088 kJ/kg
s₁ = 4.287 kJ/(kg·K)
Assuming an isentropic system, from tables, we look for the saturation temperature of saturated air at 4.287 kJ/(kg·K) which is approximately
h₂ = 79.572 kJ/kg
The saturation temperature at the given
T₂ = 79°C
The rate of work output 
= 
×
×(T₂ - T₁)
Where;
= The specific heat of air at constant pressure = 0.7177 kJ/(kg·K)
= The mass flow rate = 2.0 kg/s
Substituting the values, we have;
= 2.0 × 0.7177 × (79 - 355) = -396.17 kJ/s
= -396.17 kJ/s
Answer:
The total load carried by the fiber will be "98%".
Explanation:
The given values are:
, 
As we know,
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
Now,
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
Therefore,
The load carried by fiber,
i.e., 98%
Answer: (C) 9.14 . 10⁻³ Ω
Explanation:
The resistance of a resistor, is proportional to his length and inversely proportional to his area, being the proportionality constant a property of the material, called resistivity.
The resistivity is defined as the inverse of the electrical conductivity, which depends on the number of charge carriers and the mobility of these carriers, which is different for each material.
So, we can calculate the resistance as follows:
R = 1/σ . L / A, where:
σ = electrical conductivity, l= length of the wire , A = wire cross-section (assumed circular).
Replacing by the values, we can calculate R as follows:
R = 1/6.1. 10⁷ (Ω.m) . 8.1 m. / π (0.0043)² m / 4 = 9.14 . 10⁻³ Ω
Answer:
1. Loss of income.
2. Rental costs.
3. Utility bills.
4. Loss of rent.
5. Storage costs.
Explanation:
Liquidated damages can be defined as pre-determined damages or clauses that are highlighted or indicated at the time of entering into a contract between a contractor and a client which is mainly based on evaluation of the actual loss the client may incur should the contractor fail to meet the agreed completion date.
Generally, liquidated damages are meant to be fair rather than being a penalty or punitive to the defaulter. It is usually calculated on a daily basis for the loss.
When entering into a contract with another, liquidated damages are intended to represent anticipated losses to the owner based upon circumstances existing at the time the contract was made.
Listed below are five (5) types of potential losses to the owner that would qualify for determination of such potential losses;
1. Loss of income.
2. Rental costs.
3. Utility bills.
4. Loss of rent.
5. Storage costs.
