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mihalych1998 [28]
2 years ago
14

Please look at the picture for question.

Engineering
2 answers:
igor_vitrenko [27]2 years ago
6 0

Answer:

more than10 joules

Explanation:

Vilka [71]2 years ago
5 0

Answer:

more than 10 joules jjsjdnjdfjnfjfnjfnnfndnndjnfjgngjntjfjmrmdkdmjd

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Please help me in this assignment.
xeze [42]
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8 0
3 years ago
An open-open organ pipe is 73.5 cm long. An open-closed pipe has a fundamental frequency equal to the third harmonic of the open
Anon25 [30]

Answer:

The length of the  open closed pipe is 12.25 cm

Explanation:

In open - open organ pipe, third harmonic has Antinode to Node, Node to Node, Node to Node and Node to Antinode.

The length of the open-open organ pipe is equal to the sum of wavelength in Antinode to Node, Node to Node, Node to Node and Node to Antinode.

L = A→N + N→N + N→N + N→A

L =\frac{\lambda }{4} + \frac{\lambda }{2} + \frac{\lambda }{2} + \frac{\lambda }{4} \\\\L = \frac{ 3\lambda }{2}\\\\\lambda = \frac{2L}{3} \\\\F = \frac{V}{\lambda} = \frac{3V}{2L}

In open-closed pipe, Fundamental frequency has Antinode to Node.

Thus, length of the open-closed organ pipe is equal to the wavelength in Antinode to Node.

L = A→N

L_o = \frac{\lambda}{4} \\\\\lambda =4L_o\\\\F_o = \frac{V}{4L_o}

From the information in the question, fundamental frequency of open-closed pipe is to the third harmonic of the open-open pipe.

F₀ = F

\frac{V}{4L_o} =\frac{3V}{2L} \\\\\frac{1}{4L_o} = \frac{3}{2*73.5 \ cm}\\\\\frac{1}{L_o} = \frac{3*4}{2*73.5 \ cm}\\\\\frac{1}{L_o}  = \frac{12}{147 \ cm}\\\\L_o =  \frac{147 \ cm}{12} = 12.25 \ cm

Therefore, the length of the  open closed pipe is 12.25 cm

4 0
3 years ago
Read 2 more answers
What is the correct answer A, B, C, D
Georgia [21]

Answer:

B a lever because it can move up and down

Explanation:

8 0
3 years ago
# 45 You are driving on a two-lane highway and the vehicle behind you wants to pass. You should
hram777 [196]

Answer:

Signal the driver behind you when it is safe to pass by turning on your four-way emergency flashers.

Avoiding casualties is the top priority when driving, the other choices given do not put whether there are cars in the other lane into consideration, therefore making them incorrect. Signaling the driver when it is safe gives you the time and them the gateway to pass, making a nice interaction keep you both alive.

4 0
2 years ago
Calculate the molar heat capacity of a monatomic non-metallic solid at 500K which is characterized by an Einstein temperature of
aleksandr82 [10.1K]

Answer:

Explanation:

Given

Temperature of solid T=500\ K

Einstein Temperature T_E=300\ K

Heat Capacity in the Einstein model is given by

C_v=3R\left [ \frac{T_E}{T}\right ]^2\frac{e^{\frac{T_E}{T}}}{\left ( e^{\frac{T_E}{T}}-1\right )^2}

e^{\frac{3}{5}}=1.822

Substitute the values

C_v=3R\times (\frac{300}{500})^2\times (\frac{1.822}{(1.822-1)^2})

C_v=3R\times \frac{9}{25}\times \frac{1.822}{(0.822)^2}

C_v=0.97\times (3R)            

6 0
3 years ago
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