Ask question

Ask question

All categories

3 years ago

9

Car A has a mass of 1,200 kg and is traveling at a rate of 22km/hr. It collides with car B has a mass of 1,900 kg and is traveli

ng in the same direction at 25km/hr. Which of the following statements is true?

1 answer:

Zina [86]3 years ago

7 0

<span>The momentum before the collision is equal to the momentum after the collision</span>

You might be interested in

Describe the interaction with the sun and producers

bagirrra123 [75]

Answer: the sun's rays is one of the raw Materials recquired by plants to make food

Explanation:plants trap light used in splitting water into hydrogen ions and oxygen molecules

4 0

3 years ago

One of the most effective ways to evaluate data is to try to replicate it.

WINSTONCH [101]

It seems that you have missed the given options for the given statement above whether it is true or false. But anyway, the correct answer would be TRUE. It is true that one <span>of the most effective ways to evaluate data is to try to replicate it. Hope that this answer will help you. </span>

6 0

3 years ago

Read 2 more answers

A ball is thrown with an initial velocity of u=(10i +15j) m/s. Whan it reaches the top of it trajectory neglecting air resistanc

liraira [26]

Answer:

v = (10 i ^ + 0j ^) m / s, a = (0i ^ - 9.8 j ^) m / s²

Explanation:

This is a missile throwing exercise.

On the x axis there is no acceleration so the velocity on the x axis is constant

v₀ₓ = 10 m / s

On the y-axis velocity is affected by the acceleration of gravity, let's use the equation

v_y = $v_{oy}$ - g t

$v_{y}^2 = v_{oy}^2 - 2 g (y - y_o)$

at the highest point of the trajectory the vertical speed must be zero

v_y = 0

therefore the velocity of the body is

v = (10 i ^ + 0j ^) m / s

the acceleration is

a = (0 i ^ - g j⁾

a = (0i ^ - 9.8 j ^) m / s²

5 0

2 years ago

A pendulum takes 6.0 seconds to swing through 5 complete cycles. What is the period of the pendulum?

photoshop1234 [79]

When you look at this, you might not be sure which way to divide ...
Should you divide 6 by 5 or 5 by 6 ?

Here's a case where you can use your units to decide.

The question wants to know the 'period'. That's a length of time,
so the answer needs to have units of time.

If you divide 'cycles' be 'time', you'll get 'cycles/second'.
That's Hz. It's frequency, not time.

If you divide 'time' by 'cycles', you'll get 'seconds/cycle'.
That's time, and it's exactly the definition of 'period'.

Period = (6 seconds) / (5 cycles)

= (6 / 5) seconds/cycle

= 1.2 seconds

6 0

3 years ago

Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the

leonid [27]

Answer:

$KE_A=33\ J$

$KE_B=99\ J$

Explanation:

Given:

Let mass of the particle B be, $m_B=m$

then the mass of particle A, $m_A=3m$

Energy stored in the compressed spring, $E=132\ J$

Now when the compression of the particles with the spring is released, the spring potential energy must get converted into the kinetic energy of the particles and their momentum must be conserved.

Kinetic energy:

$\frac{1}{2}m_A.v_A^2+\frac{1}{2}m_B.v_B^2=132$

$3m.v_A^2+m.v_B^2=264$ .............................(1)

<u>Using the conservation of linear momentum:</u>

$m_A.v_A+m_B.v_B=0$

$3m.v_A+m.v_B=0$ .............................(2)

Put the value of $v_A$ from eq. (2) into eq. (1)

$3m\times (\frac{-v_B}{3})^2+m.v_B^2=264$

$v_B^2=\frac{198}{m}$ ...........................(3)

<u>Now the kinetic energy of particle B:</u>

$KE_B=\frac{1}{2}\times m_B\times v_B^2$

$KE_B=\frac{1}{2}\times m\times \frac{198}{m}$

$KE_B=99\ J$

Put the value of $v_B^2$ form eq. (3) into eq. (1):

$v_A^2=\frac{22}{m}$

<u>Now the kinetic energy of particle A:</u>

<u /> $KE_A=\frac{1}{2}m_A.v_A^2$ <u />

<u /> $KE_B=\frac{1}{2}\times 3m\times \frac{22}{m}$ <u />

$KE_A=33\ J$

6 0

3 years ago