Answer:
distance = 33.124 meters
Explanation:
To solve this question, we will use one of the equations of motion which is:
s = ut + 0.5a * t^2
where:
s is the distance that we want to get
u is the initial velocity = 0
a is the acceleration due to gravity = 9.8 m/sec^2
t is the time = 2.6 sec
Substitute with the givens in the equation to get the distance as follows:
s = ut + 0.5a * t^2
s = (0)(2.6) + 0.5(9.8)(2.6)^2
s = 33.124 meters
Hope this helps :)
normal force because it is perpendicular to the surface
(a) 328.6 kg m/s
The linear impulse experienced by the passenger in the car is equal to the change in momentum of the passenger:
where
m = 62.0 kg is the mass of the passenger
is the change in velocity of the car (and the passenger), which is
So, the linear impulse experienced by the passenger is
(b) 404.7 N
The linear impulse experienced by the passenger is also equal to the product between the average force and the time interval:
where in this case
is the linear impulse
is the time during which the force is applied
Solving the equation for F, we find the magnitude of the average force experienced by the passenger:
It is 6 g/cm3 because density cannot be negative, and it is not speed in which the unit would be m/s.
Well.....
Gravity from the sun pulls the planets torward it while inertia pulls it outward....but I guess that would be why it orbits sorry if this doesn't help but uh
