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nirvana33 [79]
3 years ago
9

A person is pulled to the right on a sled (total mass of 52.9 kg) across the surface of a frozen pond with a force of 67.7 Newto

ns so that they move with a constant velocity. What is the force of friction acting on the sled?
Physics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

67.7 N

Explanation:

Draw a free body diagram of the person on the sled.  There are four forces:

67.7 N  to the right,

friction force to the left,

weight force down,

and normal force up.

Constant velocity means 0 acceleration.

Sum of the forces in the x direction:

∑F = ma

67.7 N − F = 0

F = 67.7 N

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Answer:

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Explanation:

since all the balls starts having the same momentum after the two collisions we will apply the principal of conservation of energy

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After second collision

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combining equations 1 and 2

m1v = m1v1 + m2v2 + m3v3  ----- ( 3 )

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applying conservation of energy

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also 3m1v1 = m1v = v1 = v/3 =

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now using p1 = p2 = m1v1 = 1/2 m1v1  hence v2 = 2v1  where v1 = 1/3 v

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solving with equation 6 and 8

v3 = 2v ------ ( 9 ) ∴  v/v3 = 1/2 ---- ( 10 )

solving with equation 9 and 10

m3 = m1/3 * 1/2 = m1/6

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