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Ronch [10]
3 years ago
14

How do I find angular speed of a rotating mass

Physics
1 answer:
kobusy [5.1K]3 years ago
8 0
Angular speed is omega in radians/sec.
tangential speed = radius time omega
so take the tan speed and divide by the radius
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The acceleration due to gravity on Earth is 9.81 m/s² [down]. A hockey puck was launched from the ice with a velocity of 50.0 m/
Gwar [14]

Answer:

0 m/s.

Explanation:

When an object is shot up into the air the only force acting on it is gravity while neglecting wind. As the gravity is acting on the object it keeps decelerating till its velocity becomes 0 after which it can go no further. The maximum height of the object is at this point.

So, at its maximum height the velocity of the puck will be zero.

4 0
4 years ago
Identify each of the following clauses as independent or dependent:
gulaghasi [49]

Answer:

1st one is dependent

2nd is independent

3rd is dependent

4th is dependent

Explanation:

independent clauses are sentences that can be on their own and make sense dependent clauses don't make sense on their own

8 0
3 years ago
Which statements about braking a car are true? A)The greater the kinetic energy of a car, the longer it takes for the car to sto
NikAS [45]

Answer:

option c  

Explanation:

Kinetic energy is due to the speed of a body.

K.E = \frac{1}{2}mv^2

When speed is doubled, the kinetic energy  is quadruple.

From third equation of motion, braking distance is also proportional to square of speed. Thus, when speed is doubled, the braking distance is quadruple.

Thus, option c is correct.

3 0
3 years ago
Read 2 more answers
If the temperature is 50 degrees and the dew point is 50 degrees, will it rain?
Paul [167]
There is a possibility but not extremely likely
4 0
3 years ago
Read 2 more answers
A horizontal clothesline is tied between 2 poles, 12 meters apart. When a mass of 1 kilograms is tied to the middle of the cloth
nadya68 [22]

Answer:

The  tension on the clotheslines is  T  = 8.83 \ N

Explanation:

The  diagram illustrating this  question is  shown on the first uploaded image

From the question we are told that  

    The distance between the two poles is  d =  12 \ m

     The mass tie to the middle of the clotheslines m  =  1 \ kg

     The length at which the clotheslines sags is  l  = 4 \ m

Generally the weight due to gravity at the middle of the  clotheslines is mathematically represented as

          W =  mg

let the angle which the tension on the  clotheslines makes with the horizontal be  \theta which mathematically evaluated using the SOHCAHTOA as follows

        Tan  \theta =  \frac{ 4}{6}

=>     \theta =  tan^{-1}[\frac{4}{6} ]

=>     \theta  =  33.70^o

   So the vertical component of this  tension is  mathematically represented a  

      T_y  = 2*  Tsin \theta

Now at equilibrium the  net horizontal force is  zero which implies that

          T_y  -  mg  = 0

=>       T sin \theta  -  mg  =  0

substituting values

          T  =   \frac{m*g}{sin (\theta )}

substituting values

           T  =   \frac{1 *9.8}{2 * sin (33.70 )}

           T  = 8.83 \ N

6 0
3 years ago
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