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2 years ago

How do I find angular speed of a rotating mass

1 answer:

8 0

Angular speed is omega in radians/sec.
tangential speed = radius time omega
so take the tan speed and divide by the radius

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A mass of 0.34 kg is fixed to the end of a 1.4 m long string that is fixed at the other end. Initially at rest, he mass is made

frozen [14]

At time $t$ seconds, the mass has angular speed

$\omega = \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) t$

and hence linear speed

$v = (1.4\,\mathrm m) \omega = (1.4\,\mathrm m) \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) t$

After 8 s, its linear speed is

$v = (1.4\,\mathrm m) \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) (8\,\mathrm s) = 37.072 \dfrac{\rm m}{\rm s} \approx 37 \dfrac{\rm m}{\rm s}$

and has centripetal acceleration with magnitude

$a = \dfrac{v^2}{1.4\,\rm m} \approx 981.667\dfrac{\rm m}{\mathrm s^2} \approx 980 \dfrac{\rm m}{\mathrm s^2}$

To maintain this linear speed, by Newton's second law the required centripetal force should have magnitude

$F = (0.34\,\mathrm{kg}) a \approx 333.767\,\mathrm N \approx \boxed{330 \,\mathrm N}$

5 0

1 year ago

Explain why it is esaier to climb a mountain on a zigzag path rather than one straight up the side. is your increase in gravitat

pogonyaev

Answer:

More work done with less power

The increase in gravitational energy is the same as the height which is a function of gravitational energy is the same in both cases

Explanation:

Climbing the mountain in zigzag pattern is easier because

1. The time it takes to climb increases so that the required power or rate of doing work decreases

2. Climbing in zigzag pattern affords the use of leverages by the sides

3. Similar mechanical power gain and efficiency from using a drive screw instead of a nail to fasten items together can be achieved

The increase in gravitational energy is the same gravitational energy ~ mass × gravity ×height

6 0

3 years ago

What is the hang time when the person moves 6 m horizontally during a 1.25 m high jump?

AlekseyPX

Answer:

1 sec

Explanation:

Horizontal distance (x) = 6m

Vertical distance (y) = 1.25m

Hang time is the duration the object is in the air before it reaches maximum height.

The time of free fall is given by

t = √2y/g

g = acceleration due to gravity

t = √(2*1.25)/9.8

t = √2.5/9.8

t = 0.5secs

Hang time = 2*0.5

= 1 sec

3 0

3 years ago

Three forces of magnitude 10N, 5N and 4N act on an object in the directions North, West and East respectively. Find the magnitud

Gekata [30.6K]

Answer:

19N to the south

Explanation:

F =10N + 5N + 4N

8 0

3 years ago

What is the equation to find an angle of projectile

Ksju [112]

I do not recall the answer to this question

3 0

2 years ago