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PtichkaEL [24]
3 years ago
15

A bimetallic strip consists of two metals: A on top and B at bottom. At temperature 00C this bimetallic strip was rigidly attach

ed to the vertical wall with one end, so strip is horizontal. We know that coefficient of thermal expansion of metal A is less than coefficient of thermal expansion of metal B. Temperature starts to raise. What happens to the bimetallic strip?
a. nothing happens
b. it contracts in horizontal direction
c. it bends down
d. it bends up
e. it expands in horizontal direction
Physics
1 answer:
joja [24]3 years ago
7 0

Answer:

e. it expands in horizontal direction

Explanation:

By the law of thermal expansion of metals we know that when a metal is heated it expands due to the thermal properties of its molecules.

<u>Mathematically this expansion in its length is given by:</u>

\Delta l=l.\alpha.\Delta T

where:

l= original length of the metallic piece

\alpha= coefficient of linear expansion

\Delta T= rise in temperature

  • Here, in the given question we have a bimetallic strip with one end attached to the wall rigidly so that it is in horizontal orientation.
  • Upon heating the strip gains the temperature and expands horizontally along the length because it is <em>fixed to the wall only from one end.</em>
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Which actions are examples of conserving resources? Check all that apply.
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"A 78-year-old woman has a mean arterial pressure of 120 mm Hg and a heart rate of 60 beats/min. She has a stroke volume of 50 m
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Formulating a Hypothesis: Part I Since the investigative question has two variables, you need to focus on each one separately. T
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So, the kinetic energy of a particle is directly proportional to its mass.

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Students perform a set of experiments by placing a block of mass m against a spring, compressing the spring a distance x along a
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Increasing the angle of inclination of the plane decreases the velocity of the block as it leaves the spring.

  • The statement that indicates how the relationship between <em>v</em> and <em>x</em> changes is;<u> As </u><u><em>x</em></u><u> increases, </u><u><em>v</em></u><u> increases, but the relationship is no longer linear and the values of </u><u><em>v</em></u><u> will be less for the same value of </u><u><em>x</em></u><u>.</u>

Reasons:

The energy given  to the block by the spring = \mathbf{0.5  \cdot k  \cdot x^2}

According to the principle of conservation of energy, we have;

On a flat plane, energy given to the block = 0.5  \cdot k  \cdot x^2 = kinetic energy of

block = 0.5  \cdot m  \cdot v^2

Therefore;

0.5·k·x² = 0.5·m·v²

Which gives;

x² ∝ v²

x ∝ v

On a plane inclined at an angle θ, we have;

The energy of the spring = \mathbf{0.5  \cdot k  \cdot x^2}

  • The force of the weight of the block on the string, F = m \cdot g  \cdot sin(\theta)

The energy given to the block = 0.5 \cdot k \cdot x^2 - m \cdot g  \cdot sin(\theta) = The kinetic energy of block as it leaves the spring = \mathbf{0.5  \cdot m  \cdot v^2}

Which gives;

0.5 \cdot k \cdot x^2 - m \cdot g  \cdot sin(\theta) = 0.5  \cdot m  \cdot v^2

Which is of the form;

a·x² - b = c·v²

a·x² + c·v² = b

Where;

a, b, and <em>c</em> are constants

The graph of the equation a·x² + c·v² = b  is an ellipse

Therefore;

  • As <em>x</em> increases, <em>v</em> increases, however, the value of <em>v</em> obtained will be lesser than the same value of <em>x</em> as when the block is on a flat plane.

<em>Please find attached a drawing related to the question obtained from a similar question online</em>

<em>The possible question options are;</em>

  • <em>As x increases, v increases, but the relationship is no longer linear and the values of v will be less for the same value of x</em>
  • <em>The relationship is no longer linear and v will be more for the same value of x</em>
  • <em>The relationship is still linear, with lesser value of v</em>
  • <em>The relationship is still linear, with higher value of v</em>
  • <em>The relationship is still linear, but vary inversely, such that as x increases, v decreases</em>

<em />

Learn more here:

brainly.com/question/9134528

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