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PtichkaEL [24]
3 years ago
15

A bimetallic strip consists of two metals: A on top and B at bottom. At temperature 00C this bimetallic strip was rigidly attach

ed to the vertical wall with one end, so strip is horizontal. We know that coefficient of thermal expansion of metal A is less than coefficient of thermal expansion of metal B. Temperature starts to raise. What happens to the bimetallic strip?
a. nothing happens
b. it contracts in horizontal direction
c. it bends down
d. it bends up
e. it expands in horizontal direction
Physics
1 answer:
joja [24]3 years ago
7 0

Answer:

e. it expands in horizontal direction

Explanation:

By the law of thermal expansion of metals we know that when a metal is heated it expands due to the thermal properties of its molecules.

<u>Mathematically this expansion in its length is given by:</u>

\Delta l=l.\alpha.\Delta T

where:

l= original length of the metallic piece

\alpha= coefficient of linear expansion

\Delta T= rise in temperature

  • Here, in the given question we have a bimetallic strip with one end attached to the wall rigidly so that it is in horizontal orientation.
  • Upon heating the strip gains the temperature and expands horizontally along the length because it is <em>fixed to the wall only from one end.</em>
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Answer:

900J

Explanation:

w =f×s

60×15

=900J

thus the k.e of the body is 900j

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2 years ago
Unpolarized light passes through two polarizers whose transmission axes are at an angle # with respect to each other. What shoul
Yuki888 [10]

Answer:

63.4^{\circ}

Explanation:

When unpolarized light passes through the first polarizer, the intensity of the light is reduced by a factor 1/2, so

I_1 = \frac{1}{2}I_0 (1)

where I_0 is the intensity of the initial unpolarized light, while I_1 is the intensity of the polarized light coming out from the first filter. Light that comes out from the first polarizer is also polarized, in the same direction as the axis of the first polarizer.

When the (now polarized) light hits the second polarizer, whose axis of polarization is rotated by an angle \theta with respect to the first one, the intensity of the light coming out is

I_2 = I_1 cos^2 \theta (2)

If we combine (1) and (2) together,

I_2 = \frac{1}{2}I_0 cos^2 \theta (3)

We want the final intensity to be 1/10 the initial intensity, so

I_2 = \frac{1}{10}I_0

So we can rewrite (3) as

\frac{1}{10}I_0 =  \frac{1}{2}I_0 cos^2 \theta

From which we find

cos^2 \theta = \frac{1}{5}

cos \theta = \frac{1}{\sqrt{5}}

\theta=cos^{-1}(\frac{1}{\sqrt{5}})=63.4^{\circ}

6 0
3 years ago
How does the speed of visible light compare with the speed of gamma rays
DochEvi [55]

Answer:

They are the same

Explanation:

Electromagnetic waves consist of perpendicular oscillations of electric and magnetic field, which oscillate perpendicularly to the direction of motion of the wave (transverse wave). One property of the electromagnetic waves is that they travel in a vacuum always at the same speed, called speed of light:

c=3.0\cdot 10^8 m/s

Electromagnetic waves are classified into 7 different types according to their frequency; from highest to lowest frequency, we have:

Gamma rays

X-rays

Ultraviolet

Visible light

Infrared

Microwaves

Radio waves

We see that both visible light and gamma rays are electromagnetic waves, so they both travel in a vacuum at the same speed, the speed of light.

3 0
3 years ago
Which statement best explains the importance of resource economics?
aleksley [76]

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it sets consistent prices to achieve sustainability

7 0
2 years ago
a lead block drops its temperature by 5.90 degrees celsius when 427 J of heat are removed from it. what is the mass of the block
Airida [17]

Answer:

577g

Explanation:

Given parameters:

Temperature change = 5.9°C

Amount of heat lost = 427J

Unknown:

Mass of the block = ?

Solution:

The heat capacity of a body is the amount of heat required to change the temperature of that body by 1°C.

                H =  m c Ф

  H is the heat capacity

 m  is the mass of the block

  c is the specific heat capacity

   Ф is the temperature change

Specific heat capacity of lead is 0.126J/g°C

   m = H / m Ф

   m = \frac{427}{0.126 x 5.9}  = 577g

Mass of the lead block is 577g

7 0
3 years ago
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