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AleksAgata [21]
3 years ago
14

Ag2O(s) → 2Ag(s) + ½ O2(g) ΔH° = 31.05 kJ Which statements concerning the reaction above are true? (1) heat is released (2) heat

is absorbed (3) reaction is exothermic (4) reaction is endothermic (5) products have higher enthalpy content than reactants (6) reactants have higher enthalpy content than products A) 1, 3, and 5 B) 1, 3, and 6 C) 2, 4, and 6 D) 2, 4, and 5
Chemistry
1 answer:
Sidana [21]3 years ago
5 0

Answer:

D) 2, 4, and 5

Explanation:

In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.

If heat is absorbed in a reaction, that reaction is endothermic.

Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.

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Consider the reaction:
stich3 [128]

Answer:

\large \boxed{\text{-851.4 kJ/mol}}

Explanation:

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})

                            2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s)

ΔfH°/kJ·mol⁻¹:         0         -824.3         -1675.7         0

\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}

7 0
3 years ago
2. Classify the following solutions as acidic, basic, or neutral at 25OC.
PilotLPTM [1.2K]

Answer: a) pH = 13.00 : basic

b) [H_3O^+]=1.0\times 10^{-12}: basic

c) pOH = 5.00 : basic

d) [OH^-]=1.0\times 10^{-9}: acidic

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H_3O^+]

Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.

a) pH = 13.00

As pH is more than 7, the solution is basic.

b)  [H_3O^+]=1.0\times 10^{-12}

Putting in the values:

pH=-\log[1.0\times 10^{-12}]

pH=12

As pH is more than 7, the solution is basic.

c) pOH = 5.00

pH+pOH=14.0

pH=14.0-5.00=9.00

As pH is more than 7, the solution is basic.

d) [OH^-]=1.0\times 10^{-9}

Putting in the values:

pOH=-\log[1.0\times 10^{-9}]

pOH=9.00

pH+pOH=14.0

pH=14.0-9.00=5.00

As pH is less than 7, the solution is acidic.

3 0
3 years ago
The theoretical yield of NaBr from
Dvinal [7]

the percent yield of the reaction is 100%.

The percent yield is calculated as the experimental yield divided by the theoretical yield x 100%:

% yield = actual yield / theoretical yield * 100%

% yield of a reaction in this case Rate

In this case, the molar mass of NaBr is 102.9 g / mol, as you know:

444 actual yield = 7.08 mol x 102.9 g / mol = 728.532 g

theoretical yield = 7.08 mol x 102.9 g / mol = 728.532 g

, Replaced by the definition of percent yield:

percent yield = 728.532 grams / 728.532 grams * 100%

percent yield = 100%

Finally, the percent yield of the reaction is 100%.

<h3 />

FeBr3 is iron bromide. Also known as iron bromide. Iron bromide is an ionic compound in which iron is in a +3 oxidation state.

Learn more about % yield here:brainly.com/question/27979178

#SPJ10

5 0
2 years ago
One success of Johann Döbereiner's law of triads was that it organized most of the known elements into three-element groups base
jenyasd209 [6]
That statement is true

it was easy to organize 'all' the elements in a group of threes because back then they only knew about 15 - 20 elements

hope this helps
4 0
3 years ago
Read 2 more answers
Why are koalas so crusty?
marishachu [46]
Koalas are not crusty, but their fur is very coarse, like wool.
Hope this helps.
6 0
3 years ago
Read 2 more answers
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