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2 years ago

Which of these is NOT responsible for causing weather?

Chemistry

1 answer:

KatRina [158]2 years ago

3 0

Answer: I think it might be D

Explanation: hope it helps

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El agua oxigenada se descompone rápidamente en agua y oxígeno cuando se le agrega una peueña cantidad de dióxido de manganeso, q

katovenus [111]

Answer:

IDK

Explanation:

I dont speak spanish

6 0

4 years ago

A compound of mercury and oxygen is heated in order to decompose the compound. A 4.08 grams sample of mercury oxide upon heating

arlik [135]

Answer:

HgO (empirical formula)

Explanation:

4.08 - 3.78 = 0.3g (oxygen)

$(\frac{4.08}{201}) \: \: \: (\frac{0.3}{16} )$

0.02 : 0.02

0.02/0.02 : 0.02/0.02

1 : 1 (ratio)

HgO ( empirical formula)

2HgO ----> 2Hg + O2 ( your equation correct)

7 0

2 years ago

An Argon laser gives off pulses of green light (wavelength = 514 nm). If a single pulse from the laser has a total energy of 10.

svetoff [14.1K]

Answer:

$n=2.59\times 10^{16}$ photons

Explanation:

$E=n\times \frac{h\times c}{\lambda}$

Where,

n is the number of photons

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

$\lambda$ is the wavelength of the light

Given that, wavelength = 514 nm = $514\times 10^{-9}\ m$

Energy = 10.0 mJ = 0.01 J ( 1 mJ = 0.001 J )

Applying the values as:-

$0.01=n\times \frac{6.626\times 10^{-34}\times 3\times 10^8}{514\times 10^{-9}}$

$\frac{19.878n}{10^{17}\times \:514}=0.01$

$n=2.59\times 10^{16}$ photons

7 0

3 years ago

Positron emission of technetium-95

NNADVOKAT [17]

Idk it’s making me answer a question in order to get help on my own

5 0

3 years ago

Be sure to answer all parts. calculate δg ocell for the reaction between cr(s) and cu2+(aq). e ocell = 1.08 j/c. enter your answ

Mademuasel [1]

Answer:

$\boxed{-6.29 \times10^{5}\text{ J}}$

Explanation:

Step 1. Determine the cell potential

E°/V

2×[Cr ⟶ Cr³⁺ + 3e⁻] 0.744 V

3×[Cu²⁺ + 2e⁻ ⟶ Cu] 0.3419 V

2Cr + 3Cu²⁺ ⟶ 3Cu + 2Cr³⁺ 1.086 V

Step 2. Calculate ΔG°

$\Delta G^{\circ} = -nFE_{\text{cell}}^{^{\circ}} = -6 \times 96 485 \times 1.086 = \text{-629 000 J}\\\\= \boxed{-6.29 \times10^{5}\text{ J}}$

6 0

3 years ago