All categories

3 years ago

When a plant is entering the Calvin cycle of photosynthesis_____.

Chemistry

1 answer:

Andrei [34K]3 years ago

4 0

B). light energy is not required to proceed

Explanation:

In the Calvin cycle of photosynthesis, light energy is not required. The Calvin cycle is light independent and it is made up of a series of redox reactions.

During photosynthesis reactions, green plants manufacture their food using carbon dioxide, sunlight and water.
During the Calvin cycle aspect, light energy is not required for chemical reactions to take place. The light energy helps to move electrons.
The cycle is also known as dark reactions.
It is at this stage that carbon dioxide combines with water to form glucose.
The reaction is initiated with light energy which produces NADPH and ATP.
The Calvin cycle follows by using the NADPH and ATP to produce glucose in the dark phase.

Learn more:

ATP brainly.com/question/2953868

Light dependent reactions brainly.com/question/6866300

#learnwithBrainly

You might be interested in

Which action do researchers take to make advances in science?

melamori03 [73]

The action that researchers take to make advances in science would be conducting experiments to test their hypothesis. By doing such, they are able to know whether the hypothesis is true or not. Hope this answers the question. Have a nice day.

3 0

3 years ago

Read 2 more answers

2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo

pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

Chemical reaction involved: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol) (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: $Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2$

To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:

$\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}$

$\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)$

$\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)$

Therefore, the Gibb's free energy change at 37° C (310.15 K): ΔG = (-2.45 kJ/mol)

4 0

3 years ago

What is the osmotic pressure of a 100 ml of toluene solution that contains a total of 0.005 moles of a polymer dissolved in it a

allsm [11]

Osmotic pressure is the pressure that would have to be applied to a pure solvent to prevent it from passing into a given solution by osmosis.

That can be mathematical computed from the expression:

Osmotic pressure=C×R×T

Where,

C= Concentration

R=Gas constant

T=Temperature

Concentration=Number of moles of solute/Volume(L)

=0.005*1000/100

=0.05

R= 0.08206 atm L/mol K

T=25+273

=298

Osmotic pressure= 0.05×0.08206×298

=1.2 atm

4 0

3 years ago

Sort the sentences based on whether they describe the properties of a heterogeneous or a homogenous mixture.

klasskru [66]

Homogeneous Mixture:
It may be mistaken for a pure substance.
It can be separated using distillation

Heterogeneous Mixture:
Its components are visible
It can be separated using distillation.
Concrete is an example of this kind of mixture.

Hope this helps!

5 0

3 years ago

Read 2 more answers

What volume of Co2 (carbon (iv) oxide)

hram777 [196]

Answer:

2.1056L or 2105.6mL

Explanation:

We'll begin by calculating the number of mole in 10g of Na2CO3. This can be obtained as follow:

Molar mass of Na2CO3 = (23x2) + 12 + (16x3) = 106g/mol

Mass of Na2CO3 = 10g

Mole of Na2CO3 =.?

Mole = mass /molar mass

Mole of Na2CO3 = 10/106

Mole of Na2CO3 = 0.094 mole

Next, we shall determine the number of mole CO2 produced by the reaction of 0.094 mole of Na2CO3. This is illustrated below:

Na2CO3 + 2HCl —> 2NaCl + H2O + CO2

From the balanced equation above,

1 mole of Na2CO3 reacted to produce 1 mole of CO2.

Therefore, 0.094 mole of Na2CO3 will also react to 0.094 mole of CO2.

Next, we shall determine the volume occupied by 0.094 mole of CO2 at STP. This is illustrated below:

1 mole of a gas occupy 22.4L at STP. This implies that 1 mole CO2 occupies 22.4L at STP.

Now, if 1 mole of CO2 occupy 22.4L at STP, then, 0.094 mole of CO2 will occupy = 0.094 x 22.4 = 2.1056L

Therefore, the volume of CO2 produced is 2.1056L or 2105.6mL

7 0

3 years ago