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loris [4]
3 years ago
10

What are the three types of friction and when does each apply

Physics
2 answers:
Elina [12.6K]3 years ago
6 0

Answer:

Static, sliding, and rolling

Explanation:

Static friction acts on objects when they are resting on a surface.

Sliding friction is friction that acts on objects when they are sliding over a surface. Sliding friction is weaker than static friction.

Rolling friction is friction that acts on objects when they are rolling over a surface. Rolling friction is much weaker than sliding friction or static friction.

padilas [110]3 years ago
3 0

Answer:static, sliding, rolling,

Explanation:

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A vector → A has a magnitude of 56.0 m and points in a direction 30.0° below the negative x axis. A second vector, → B , has a m
MissTica

Answer:

  • The magnitude of the vector \vec{C} is 107.76 m

Explanation:

To find the components of the vectors we can use:

\vec{A} = | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )

where | \vec{A} | is the magnitude of the vector, and θ is the angle over the positive x axis.

The negative x axis is displaced 180 ° over the positive x axis, so, we can take:

\vec{A} = 56.0 \ m \ ( \ cos( 180 \° + 30 \°) \ , \ sin (180 \° + 30 \°) \ )

\vec{A} = 56.0 \ m \ ( \ cos( 210 \°) \ , \ sin (210 \°) \ )

\vec{A} = ( \ -48.497 \ m \ , \ - 28 \ m \ )

\vec{B} = 82.0 \ m \ ( \ cos( 180 \° - 49 \°) \ , \ sin (180 \° - 49 \°) \ )

\vec{B} = 82.0 \ m \ ( \ cos( 131 \°) \ , \ sin (131 \°) \ )

\vec{B} = ( \ -53.797 \ m \ , \ 61.886\ m \ )

Now, we can perform vector addition. Taking two vectors, the vector addition is performed:

(a_x,a_y) + (b_x,b_y) = (a_x+b_x,a_y+b_y)

So, for our vectors:

\vec{C} = ( \ -48.497 \ m \ , \ - 28 \ m \ ) + ( \ -53.797 \ m \ ,  ) = ( \ -48.497 \ m \ -53.797 \ m , \ - 28 \ m \ + \ 61.886\ m \ )

\vec{C} = ( \ - 102.294 \ m , \ 33.886 m \ )

To find the magnitude of this vector, we can use the Pythagorean Theorem

|\vec{C}| = \sqrt{C_x^2 + C_y^2}

|\vec{C}| = \sqrt{(- 102.294 \ m)^2 + (\ 33.886 m \)^2}

|\vec{C}| =107.76 m

And this is the magnitude we are looking for.

5 0
3 years ago
How is thermal energy transferred during convection?
Lerok [7]
Conduction and <span>convection it involves particles.</span>
5 0
4 years ago
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What is the force needed to move an 225 kg car a distance of 150 meters
Kobotan [32]

Physics

mass = 225 kg

weight = m × a = 2250 N

distance = 150 m

force : ______?

Answers :

W = F × s

W = 2250 × 150

W = 337500 ✅

4 0
3 years ago
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You are asked to find a set of dimensionless parameters to organize data from a laboratory experiment, in which a tank is draine
mihalych1998 [28]

Answer:

Step 1

Given: A tank is drained through an orifice from initial liquid level (h₀). The time(r), to  drain the tank, depends on tank diameter (D), orifice diameter (d), acceleration due to gravity (g), liquid density (ρ) and liquid viscosity  (μ).

r = f (h₀, D, d, g, ρ, μ)

Step 2

There are totally seven parameters r, h₀, D, d, g, ρ and μ

∴ n = 7

The primary variables are M, L, T

∴ m = 3

So, the number of repeating variables are, r = 3

Select the three repeating variables are ρ, d, g

Then according to Buckingham, there will be n-m (⇒ 7-3 = 4) dimensionless groups given by π₁, π₂, π₃ and π₄

So, The number of π terms = 4

Explanation:

See attached images for step 3 to 7

6 0
3 years ago
A pendulum is made of a small sphere of mass 0.250 kg attached to a lightweight string 1.20 m in length. As the pendulum swings
olchik [2.2K]

Answer:

0.833 N

Explanation:

Formula for Kinetic Energy E_k = \frac{mv^2}{2}

Formula for Potential Energy E_p = mgy

First we need to find the vertical distance between the maximum-angle position and the pendulum lowest point:

Using the swinging point as the reference, the vertical distance from the maximum-angle (34 degree) position to the swinging point is:

L * cos(34^o) = 1.2cos(34^o) = 1.2*0.83 = 0.995 \approx 1 m

At the lowest position, pendulum is at string length to the swinging point, which is 1.2 m. Therefore, the vertical distance between the maximum-angle position and the pendulum lowest point would be

y = 1.2 - 1 = 0.2 m.

As the pendulum is traveling from the maximum-angle position to the lowest point position, its potential energy would be converted to the kinetic energy.

By law of energy conservation:

E_k = E_p

\frac{mv^2}{2} = mgy

v^2 = 2gy

v = \sqrt{2gy}

Substitute g = 10 m/s^2 and y = 0.2 m:

v = \sqrt{2 * 10 * 0.2} = \sqrt{4} = 2 m/s

At lowest point, pendulum would generate centripetal tension force on the string:

F = m\frac{v^2}{L}

We can substitute mass m = 0.25, rotation radius L = 1.2 m and v = 2 m/s:

F = 0.25\frac{2^2}{1.2} = 0.833 N

5 0
3 years ago
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