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3 years ago

What are the three types of friction and when does each apply

Physics

2 answers:

Elina [12.6K]3 years ago

6 0

Answer:

Static, sliding, and rolling

Explanation:

Static friction acts on objects when they are resting on a surface.

Sliding friction is friction that acts on objects when they are sliding over a surface. Sliding friction is weaker than static friction.

Rolling friction is friction that acts on objects when they are rolling over a surface. Rolling friction is much weaker than sliding friction or static friction.

padilas [110]3 years ago

3 0

Answer:static, sliding, rolling,

Explanation:

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sineoko [7]

<h2><u>Given</u>:</h2>

Horizontal distance between two boats = x = 14 m

One boat is at trough, the other is at crest.

As there is no crests between them meaning the boat are next to each other.

Wavelength is the distance between two consecutive crests/troughs = w

The distance between a crest and a trough next to it = w/2

Complete cycles = c = 5

Time taken for c cycles = t = 15 s

Vertical distance between two boats = y = 2.4 m

wavelength = w = 2x = 28 m

Amplitude = A = Displacement from mean to extreme position = y/2 = 1.2 m

Time period for one cycle = T = t/c = 15/5 = 3 s/cycle

frequency = 1/T = 1/3 = 0.33 hertz

speed = wavelength/Period = w/T = 28/3 = 9.33 m/s

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3 years ago

Most of the resistance of the human body comes from the skin, as the interior of the body contains aqueous solutions that are go

ruslelena [56]

Answer:

a) Resistivity=R.A/L

Here, R=500000ohm, L=1.6m, A=2pi* (0.14/2)*0.002 m2=0.00088.........we have converted quantities into SI units

Resistivity=R.A/L

=500000*0.00088/1.6 = 440/1.6= 275 ohm.meter

b) pskin/pinterior =275/4.8=57.3

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4 years ago

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Pachacha [2.7K]

Answer:

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Explanation:

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2 years ago

Read 2 more answers

Two forces of 8N and 10N CANNOT give a resultant of<br><br> a. 1 N<br> b. 2 N<br> c. 9 N<br> d. 18 N

Lelechka [254]

Answer:

I believe it is D

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3 years ago

You are in your car driving on a highway at 23 m/s when you glance in the passenger-side mirror (a convex mirror with radius of

Irina-Kira [14]

Answer:

v = 26. 88 m/s +23 m/s

Explanation:

u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m

$\frac{1}{s} +\frac{1}{s'} = \frac{2}{R}$

$\frac{1}{2.0 m} +\frac{1}{s'} = \frac{2}{1.50 m}$

Solve s'

$\frac{1}{s'} = \frac{2}{1.50 m} - \frac{1}{2.0 m}$

$\frac{1}{s'} = 1.833 m$

$s' = - 0.545 m$

To determine the speed of the trick to the highway

$\frac{ds}{dt}= \frac{s^2* \frac{ds}{dt}}{s' ^2} =\frac{2.0 ^2m * 2.0 m/s}{0.545^2m}$

$\frac{ds}{dt} = 26.88 m/s$

Now to determine the velocity highway is going to be

v = ds/dt + u

v = 26. 88 m/s +23 m/s

8 0

4 years ago