When there is no air resistance, objects of different masses dropped from rest
1 answer:
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Answer:
P₂ = 1.22 kPa
Explanation:
This problem can be solved using the equation of state:
where,
P₁ = initial pressure = 1 KPa
P₂ = final pressure = ?
V₁ = initial Volume = 1 liter
V₂ = final volume = 1.1 liter
T₁ = initial temperature = 290 k
T₂ = final temperature = 390 k
Therefore,
<u>P₂ = 1.22 kPa</u>
Answer:
0.8976 seconds
Explanation:
The period of oscillation for the simple harmonic motion can be found using the formula ...
T = 2π√(d/g)
where d is the displacement of the spring due to the attached weight, and g is the acceleration due to gravity.
__
For d = 0.20 meters, the period is ...
T = 2π√(0.20/9.8) ≈ 0.8976 . . . . seconds
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<em>Additional comment</em>
The formula for the oscillator period is usually seen as ...
T = 2π√(m/k)
where m is the mass in the system and k is the spring constant. The value of the spring constant is calculated from ...
k = mg/d
Using that in the formula, we find it simplifies to ...