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Leni [432]
3 years ago
10

Prior to determining the experimental design, a scientist typically? A. makes observations. B. forms a hypothesis. C. performs a

n experiment. D. predicts the result of an experiment.
Physics
1 answer:
Umnica [9.8K]3 years ago
7 0

Prior to determining the experimental design, a scientist typically forms a hypothesis. The answer is letter B. this is to prepare the scientist, the possible outcome of their research before the experimental design whether they are wrong or not.

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What is the best approximate value for the elastic potential energy (EPE) of the spring elongated by 3.0 meters?
klasskru [66]

P.E=0.0675 J

Explanation:

Elastic potential Energy=Force × distance of displacement

The formula to apply is;

P.E=1/2 ks²

where k is the spring constant given as; 1.5 *10^-2 N/m  and s is the displacement

In this case,

s=3

P.E= 1/2 * 1.5 × 10^-2 ×3²

P.E=1.5×10^-2*4.5

P.E=0.0675 J

Learn More

Elastic potential energy:brainly.com/question/1352053

Keywords: approximate,value,elastic potential energy,spring, elongated

#LearnwithBrainly

7 0
3 years ago
A person is able to pull a rope with a force of 700 N. What is the minimum number of fixed and moveable pulleys that the person
Sav [38]

<u>Answer: </u>

C option is  correct

20 movable and 20 fixed pulleys required

<u>Explanation: </u>

To lift a 27,800 N elephant with a 700 N drive,  

27800/700=39.7  

the individual requires a mechanical favorable position of 39.7 which is equivalent to 40. A solitary movable pulley gives a mechanical favorable position of 2, two portable pulleys yield a mechanical preferred standpoint of 4, and a framework with three movable pulleys results in a mechanical favorable position of 6. In light of this example, 20 movable pulleys and 20 fixed are required to give a mechanical preferred standpoint of 40

8 0
3 years ago
Read 2 more answers
Mercury has a radial acceleration of 3.96 × 10−2 m/s2 and its orbital period is T = 88 days. What is the radius of Mercury’s orb
Maslowich

Answer: 58,045,522,878.8 meters

Explanation:

Ok, the data we have is

Period = T = 88 days

Radial acceleration = ar = 3.96x10^-2 m/s^2

And we know that the equation for the radial acceleration is:

ar = v^2/r = r*w^2

Where v is the velocity. r is the radius and w is the angular velocity.

And we know that:

w = 2*pi*f

where f is the frequency, and:

T = 1/f.

Then we can write:

w = 2*pi/T

and our equation becomes:

ar = r*(2*pi/T)^2

Now we solve this for r.

First we need to use the same units in both equations, so we want to write T in seconds.

T = 88 days,

A day has 24 hours, and one hour has 3600 seconds:

T = 88*24*3600 s =7,603,200s

Then:

3.96x10^-2 m/s^2 = r*(2*3.14/7,603,200s)^2

r = (3.96x10^-2 m/s^2) /(2*3.14/7,603,200s)^2 = 58,045,522,878.8 meters

5 0
4 years ago
. An object has a position given by ~r(t) = [3.0 m − (4.00 m/s)t]ˆı + [6.0 m − (8.00 m/s2 )t 2 ]ˆ , where all quantities are in
kupik [55]

Answer:

(c) 16 m/s²

Explanation:

The position is r(t) = [3.0 \text{ m} - (4.00 \text{ m/s})t]\hat{i} + [6.0 \text{m} - (8.00 \text{ m/s}^2 )t^2 ]\hat{j}.

The velocity is the first time-derivative of <em>r(t).</em>

<em />v(t) = \dfrac{d}{dt}r(t) = -4.00\,\hat{i} -16t\,\hat{j}<em />

The acceleration is the first time-derivative of the velocity.

a(t) = \dfrac{d}{dt} v(t) = -16\hat{j}

Since <em>a(t)</em> does not have the variable <em>t</em>, it is constant. Hence, at any time,

a = -16\hat{j}

Its magnitude is 16 m/s².

4 0
3 years ago
A 38.5kg man is in an elevator accelerating downward. A normal force of 343n pushes up on him. what is his acceleration?
alexira [117]

Answer:

<h3>The answer is 8.91 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{343}{38.5}  =  \frac{98}{11}  \\  = 8.909090...

We have the final answer as

<h3>8.91 m/s²</h3>

Hope this helps you

4 0
3 years ago
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