An astronaut is moving in space when a big explosion occurs about 50 metres BEHIND him. How will the astronaut come to know abou
2 answers:
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Answer:
The appropriate solution is "61.37 s".
Explanation:
The given values are:
Boat moves,
= 10 m/s
Water flowing,
= 1.50 m/s
Displacement,
d = 300 m
Now,
The boat is travelling,
=
=
Travelling such distance for 300 m will be:
⇒
On putting the values, we get
Throughout the opposite direction, when the boat seems to be travelling then,
=
=
Travelling such distance for 300 m will be:
⇒
On putting the values, we get
hence,
The time taken by the boat will be:
=
=
Answer:
Option E is correct 310N
Explanation:
Given that the force used to push the crate is F = 200N
The force directed 20° below the horizontal
Mass of crate is m = 25kg
Weight of the crate can be determine using
W = mg
g is gravitational constant =9.8m/s²
W = 25×9.8
W = 245 N
Check attachment. For free body diagram and better understanding
Using newton second law along the vertical axis since we want to find the normal force
ΣFy = m•ay
ay = 0, since the body is not moving in the vertical or y direction
N—W—F•Sin20 = 0
N = W+F•Sin20
N = 245+ 200Sin20
N = 245 + 68.4
N = 313.4 N
The normal force is approximately 310 N to the nearest ten
