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Misha Larkins [42]
3 years ago
11

The reason an astronaut in an earth satellite feels weightless is thatThe reason an astronaut in an earth satellite feels weight

less is thatthe astronaut is falling.the astronaut is at a point in space where the effects of the moon's gravity and the earth's gravity cancel.the astronaut's acceleration is zero.this is a psychological effect associated with rapid motion.the astronaut is beyond the range of the earth's gravity.
Physics
2 answers:
ozzi3 years ago
8 0

The reason an astronaut in an earth satellite feels weightless is that the astronaut is falling.

Option a

<u>Explanation: </u>

The other options except Option is not applicable since the gravitational force is a long range force, in which the satellite revolves very close to the surface of the Earth where the gravity is felt.The zero weight experienced by the astronaut in a satellite is due to the earth pulling along with satellite. Due to gravitational force of the Earth,the astronaut falls freely .

But why not the satellite comes down due to gravity when its launched in space. The fact is that the satellite is launched with velocity of tangent direction and it is very high. The centripetal force balances the gravity.

madreJ [45]3 years ago
8 0

Answer:

There is less gravity

Explanation:

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DerKrebs [107]

Answer:

0.0549 m

Explanation:

Given that

equation y(x,t)=Acos(kx−ωt)

speed  v = 8.5 m/s

amplitude A = 5.5*10^−2 m

wavelength λ   = 0.5 m

transverse displacement = ?

v = angular frequency / wave number

and

wave number = 2π/ λ

wave number =  2 * 3.142 / 0.5

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angular frequency = v k

angular frequency = 8.5 * 12.568

angular frequency = 106.828 rad/sec ~= 107 rad/sec

so

equation y(x,t)=Acos(kx−ωt)

y(x,t)= 5.5*10^−2 cos(12.568 x−107t)

when x =0 and and t = 0

maximum y(x,t)= 5.5*10^−2 cos(12.568 (0) − 107 (0))

maximum y(x,t)= 5.5*10^−2  m

and when x =  x = 1.52 m and t = 0.150 s

y(x,t)= 5.5*10^−2 cos(12.568 (1.52) −107(0.150) )

y(x,t)= 5.5*10^−2 × (0.9986)

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so the transverse displacement is  0.0549 m

5 0
3 years ago
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Answer:

The value of each charge is 4.22 x 10⁻⁵ C

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Therefore, the value of each charge is 4.22 x 10⁻⁵ C

7 0
3 years ago
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Hope this helps


3 0
3 years ago
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Therefore, Data D has the largest range.
3 0
3 years ago
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