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Misha Larkins [42]
4 years ago
11

The reason an astronaut in an earth satellite feels weightless is thatThe reason an astronaut in an earth satellite feels weight

less is thatthe astronaut is falling.the astronaut is at a point in space where the effects of the moon's gravity and the earth's gravity cancel.the astronaut's acceleration is zero.this is a psychological effect associated with rapid motion.the astronaut is beyond the range of the earth's gravity.
Physics
2 answers:
ozzi4 years ago
8 0

The reason an astronaut in an earth satellite feels weightless is that the astronaut is falling.

Option a

<u>Explanation: </u>

The other options except Option is not applicable since the gravitational force is a long range force, in which the satellite revolves very close to the surface of the Earth where the gravity is felt.The zero weight experienced by the astronaut in a satellite is due to the earth pulling along with satellite. Due to gravitational force of the Earth,the astronaut falls freely .

But why not the satellite comes down due to gravity when its launched in space. The fact is that the satellite is launched with velocity of tangent direction and it is very high. The centripetal force balances the gravity.

madreJ [45]4 years ago
8 0

Answer:

There is less gravity

Explanation:

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Canopus, which is in the constellation of Carina and Argo Navis, is 310 ly away. You plan a sight-seeing vacation for Canopus an
vazorg [7]

Answer:

D'=2.933*10^{18}m

Explanation:

From the question we are told that:

Distance D=310ly

Where

1ly=9.46*10^{15}

Generally the equation for  meters will you traverse to reach your vacation destination is mathematically given by

D'=D*1ly

D'=310*9.46*10^{15}

D'=2.933*10^{18}m

6 0
3 years ago
Use Coulomb’s law to derive the dimension for the permittivity of free space. <br><br><br><br>​
MrRa [10]

Answer:

Coulomb's law is:

F = \frac{1}{4*pi*e0} *(q1*q2)/r^2

First, force has units of Newtons, the charges have units of Coulombs, and r, the distance, has units of meters, then, working only with the units we have:

N = (1/{e0})*C^2/m^2

then we have:

{e0} = C^2/(m^2*N)

And we know that N = kg*m/s^2

then the dimensions of e0 are:

{e0} = C^2*s^2/(m^3)

(current square per time square over cubed distance)

And knowing that a Faraday is:

F = C^2*S^2/m^2

The units of e0 are:

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7 0
3 years ago
All of the following except ______ were part of RCA. A. Westinghouse B. Columbia Broadcasting System C. United Fruit Company D.
PSYCHO15rus [73]

Answer:

Columbia broadcasting system was never been a part of RCA corporation. The other companies Westinghouse, united fruit company and general electric were remain as part of RCA.

Explanation:

7 0
3 years ago
A Cessna 150 aircraft has a lift-off speed of approximately 125 km/h. What minimum constant acceleration does this require if th
aivan3 [116]

Answer:

Part a)

a = 3.65 m/s^2

Part b)

t = 9.5 s

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Explanation:

Part a)

As we know that it starts from rest and moves on runway by total distance 165 m

so we will have

v_f^2 - v_i^2 = 2ad

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a = 3.65 m/s^2

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Now for take off time we will have

v_f - v_i = at

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t = 9.5 s

Part c)

v_f = v_i + at

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7 0
3 years ago
every morning Tom walks along a straight road from his home to a bus stop,a distance of 160 meters.The graph shows his journey o
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Answer:

Tom walked until he was 100 metres from his home. Then, he realised that he had dropped his homework, so he turned around and went 60 metres to pick it up again. He again turned back and started to walk faster to get to the bus stop on time. He got to the bus stop 100 seconds after leaving his home and waited for the bus.

Explanation:

4 0
3 years ago
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