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Misha Larkins [42]
3 years ago
11

The reason an astronaut in an earth satellite feels weightless is thatThe reason an astronaut in an earth satellite feels weight

less is thatthe astronaut is falling.the astronaut is at a point in space where the effects of the moon's gravity and the earth's gravity cancel.the astronaut's acceleration is zero.this is a psychological effect associated with rapid motion.the astronaut is beyond the range of the earth's gravity.
Physics
2 answers:
ozzi3 years ago
8 0

The reason an astronaut in an earth satellite feels weightless is that the astronaut is falling.

Option a

<u>Explanation: </u>

The other options except Option is not applicable since the gravitational force is a long range force, in which the satellite revolves very close to the surface of the Earth where the gravity is felt.The zero weight experienced by the astronaut in a satellite is due to the earth pulling along with satellite. Due to gravitational force of the Earth,the astronaut falls freely .

But why not the satellite comes down due to gravity when its launched in space. The fact is that the satellite is launched with velocity of tangent direction and it is very high. The centripetal force balances the gravity.

madreJ [45]3 years ago
8 0

Answer:

There is less gravity

Explanation:

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s344n2d4d5 [400]

Answer:

In one rotation, the large wheel turns 4m.

Explanation:

The given values are:

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Mechanical advantage,

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As we know,

⇒ Out. \ Distance = \frac{Inp. \ distance}{Mechanical \ advantage}

On putting the values, we get

⇒                         =\frac{0.64}{0.16}

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3 years ago
What is the time required for an object starting
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A particle with charge 8 µC is located on the x-axis at the point −10 cm , and a second particle with charge 3 µC is placed on t
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towards left

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a car is moving 8.80 m/s when it begins to accelerate at 2.45 m/s^2. how much time does it take to trav 138m. please help me (':
Ulleksa [173]

Answer:

7.6 s

Explanation:

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v^{2}=u^{2}+2as

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Making v the subject then

v=\sqrt{u^{2}+2as}

Substituting 8.8 m/s for u, 138 m for s and 2.45 m/s2 for a then

v=\sqrt{8.8^{2}+2*2.45*138}\\v=27.45 m/s

Also, v=u+at and making t the subject of the formula

t=\frac {v-u}{a}

Substituting 27.45 m/s for v, 8.8 m/s for u and 2.45 m/s for a then

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3 years ago
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