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Effectus [21]
3 years ago
14

How many atoms are in potassium iodide,ki

Chemistry
2 answers:
LenKa [72]3 years ago
8 0
Use the subscripts to figure the questions out. since there is not subscript for either of these, you have one of each. meaning you have 2 atoms
timurjin [86]3 years ago
3 0
Clap your hands each part word you eat and you will get your answer.
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What does the atomic mass of an element on the periodic table represent?
Lynna [10]
The atomic mass on the periodic table represents the sum of number of protons and number of neutrons.

Atomic mass = Number of protons + number of neutrons

Hope this helps!
3 0
3 years ago
A Proton is positively (+1) charged particle and the mass 1.6727 x 10-^24 g
AVprozaik [17]

The sub-atomic particles of an atom are the proton, electron and the neutron. An electron has a charge of -1 and a smaller mass than a proton. Proton has the same mass with the neutron. The ratio between the mass of a proton and an electron is about 2000. An electron has an equal value but negative charge with the proton.

6 0
3 years ago
The volume of a gas at 2.0 atm is 3.0 L. What is the volume of the gas at 1.5 atm at the same temperature?
Andru [333]

<u>Answer:</u> The final volume of the gas comes out to be 4 L.

<u>Explanation:</u>

To calculate the volume with changing pressure, we use the equation given by Boyle's law.

This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

Mathematically,

P\propto \frac{1}{V}      (At constant temperature and number of moles)

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=2.0atm\\V_1=3L\\P_2=1.5atm\\V_2=?L

Putting values in above equation, we get:

2atm\times 3L=1.5atm\times V_2\\\\V_2=4L

Hence, the final volume of the gas will be 4 L.

4 0
3 years ago
Read 2 more answers
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Explanation:

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3 years ago
How can you prove copper is a catalyst?
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3 0
3 years ago
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