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Alika [10]
2 years ago
9

A chemical equation is shown below. KNO3 → KNO2 + O2 What are the coefficients that should be added to balance this equation? Us

e complete sentences to explain your answer. Explain how this chemical reaction demonstrates the conservation of mass.
Chemistry
2 answers:
Katarina [22]2 years ago
4 0

Answer:

Part 1: 2KNO3 → 2KNO2 + O2 is the balanced equation.

Part 2: The conversation of mass that demonstrates that there is  no detectable change in the total quantity of matter present in the

Explanation:

Part 1: To balance a chemical equation, the number of atoms in the reactants and the products must be equal. So, the coefficient 2 added before KNO3 and KNO2 to balance the equation.

2KNO3 → 2KNO2 + O2

Part 2:

This chemical reaction demonstrates the conversation of mass that demonstrates that there is  no detectable change in the total quantity of matter present when chemical change occurs (matter converts from one type to another) or physical change occurs (changes among solid, liquid, or gaseous states).

This is clear in the balanced equation.



neonofarm [45]2 years ago
4 0

<u>Answer: </u>The coefficient '2' must be added infront of KNO_3 and KNO_2 in order to balance a chemical reaction.

<u>Explanation:</u>

Law of conservation of mass states that the mass can neither be created nor be destroyed, but it can only be transformed from one form to another. It always remain conserved.

In a chemical reaction, the number of individual atoms on the reactant side must be equal to the number of individual atoms on the product side. All the balanced chemical reactions follow law of conservation of mass.

For the given chemical reaction, the balanced equation follows:

2KNO_3\rightarrow 2KNO_2+O_2

<u>On reactant side:</u>

Number of potassium atoms = 2

Number of nitrogen atoms = 2

Number of oxygen atoms = 6

<u>On product side:</u>

Number of potassium atoms = 2

Number of nitrogen atoms = 2

Number of oxygen atoms = 6

Thus, the coefficient '2' must be added infront of KNO_3 and KNO_2 in order to balance a chemical reaction.

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If the volume of wet gas collected over water is 85.0 mL at 20°C and 760 mm Hg , what is the volume of dry gas at STP conditions
dimulka [17.4K]

Answer: 77.4 mL

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of dry gas = (760 - 17.5) mmHg= 742.5 mm Hg

P_2 = final pressure of dry gas at STP =  760 mm Hg

V_1 = initial volume of dry gas = 85.0 mL

V_2 = final volume of dry gas at STP = ?

T_1 = initial temperature of dry gas = 20^oC=273+20=293K

T_2 = final temperature of dry gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final volume of wet gas at STP

\frac{742.5mmHg\times 85.0ml}{293K}=\frac{760mmHg\times V_2}{273K}

V_2=77.4mL

Volume of dry gas at STP is 77.4 mL.

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The volume of the earth is approximately 1.08326x10 to the 12th power km to the 3rd power. How many liters is this
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Here, we are required to determine the volume of the earth which is 1.08326 × 10¹² km³ in liters.

<em>The volume of the earth is approximately</em>,

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By conversion factors;

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The conversion factor from 1km³ to liters is therefore, c.f = 10¹²liters/km³

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<em>1.08326 × 10¹² km³ × 10¹²liters/km³ </em>

The volume of the earth is approximately,

1.08326 × 10²⁴ liters.

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