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kondaur [170]
3 years ago
14

Which image(s) would be considered pure substances? A) V B) I and II C) II and IV D) III and V

Chemistry
2 answers:
Nata [24]3 years ago
7 0

V is the answer for this question

Blizzard [7]3 years ago
6 0

The answer is V but i could be wrong

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at atmoshperic pressure, a balloon contains 2.00L of nitrogen of gas. How would the volume change if the Kelvin temperature were
Nataly [62]

<u>Answer:</u> The percent change in volume will be 25 %

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=2L\\T_1=T_1\\V_2=?\\T_2=75\% \text{ of }T_1=0.75\times T_1

Putting values in above equation, we get:

\frac{2L}{T_1}=\frac{V_2}{0.75\times T_1}\\\\V_2=\frac{2\times 0.75\times T_1}{T_1}=1.5L

Percent change of volume = \frac{\text{Change in volume}}{\text{Initial volume}}\times 100

Percent change of volume = \frac{(2-1.5)}{2}\times 100=25\%

Hence, the percent change in volume will be 25 %

5 0
3 years ago
Please help I need these answers
Burka [1]

Answer:

2 a

element pure form cannot broken down

3 b

Chemical change chemical R×N

(R×N = reaction)

4c homogeneous solution

Yield = Yield (reaction yield): A measure of a chemical reaction's efficiency, as a ratio of moles of product to moles of reactant. Usually expressed as a percentage. % Yield = Moles of product.

Explanation:

5 0
3 years ago
Balance the following chemical equation <br> __Mg+__O2–&gt;__MgO
mario62 [17]

Answer:

2Mg^+ +O2 right arrow 2MgO

Explanation:

6 0
3 years ago
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Mixing baking soda and vinegar is an example of an endothermic reaction. This means...
Murrr4er [49]

Answer: think a

Explanation:

6 0
2 years ago
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Calculate the pH of a solution created by placing 2.0 grams of yttrium hydroxide, Y(OH)3, in 2.0 L of H2O. Ksp for Y(OH)3 is 6.0
oee [108]

Answer:

pH = 8.314

Explanation:

  • Y(OH)3(s) ↔ Y+  +  3OH-

equil:   S               S         3S

∴ Ksp = [ Y+ ] * [ OH- ]³ = 6.0 E-24

⇒ 6.0 E-24 = ( S )*( 3S )³

⇒ 6.0 E-24 = 27S∧4

⇒ 2.22 E-25 = S∧4

⇒ ( 2.22 E-25 )∧(1/4) = S

⇒ S = 6.866 E-7 M

⇒ [ OH- ] = 3*S =2.06 E-6 M

⇒ pOH = - Log [ OH- ]

⇒ pOH = - Log ( 2.06 E-6 )

⇒ pOH = 5.686

∴ pH = 14 - pOH

⇒ pH = 8.314

8 0
3 years ago
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