What change would increase the amount of solid solute able to be dissolved in liquid water?
2 answers:
You might be interested in
Answer:
The final pressure of the gas comes out to be 303.9 KPa
Explanation:
Initial volume of gas = V = 750 mL
Initial pressure of gas = P = 101.3 KPa
Final volume of gas = V' = 250 mL
Assuming final pressure of the gas to be P' KPa.
Assuming temperature to be kept constant.
The final pressure can be obtained by following expression shown below
Final pressure of gas = 303.9 KPa
Explanation:
The given data is as follows.
Mass of ice dropped = 325 g
Initial temperature = = (30 + 273) K = 303 K
Final temperature = = (0 + 273) K = 273 K
Now, using density of water calculate the mass of ice as follows.
= 500 g
As the relation between heat energy, specific heat and change in temperature is as follows.
Q =
=
= 62750 J
Also, relation between heat energy and latent heat of fusion is as follows.
Q = m L
=
= 108300 J
Therefore, we require heat but we have 40774.95 J.
So,
=
= 188.4 g
Hence, the mass of ice = 325 g - 188.4 g
= 137 g
Therefore, we can conclude that 137 g of ice will still be present when the contents of the pitcher reach a final temperature.
Answer:
Refer to the attachment
