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11111nata11111 [884]
2 years ago
11

How would you prepare 100 ml of 0.4 M MgSO4 from a stock solution of 2 M MgSO4?

Chemistry
1 answer:
miss Akunina [59]2 years ago
7 0
OK, so to answer this question, you will simply use the molality equation which is as follows:
<span>M1V1 = M2V2 
In the givens you have:
M1 = 2M
V1 is the unknown
M2 = 0.4M
V2 = 100 ml

</span>plug in the givens in the above equation:
<span>2 x V1 = 0.4 x 100 
</span>therefore:
V1 = 20 ml

Based on this: you should take 20 ml of the 2 M solution and make volume exactly 100 ml in a volumetric flask by diluting in water.

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Ionic compounds are compound formed from the transfer of electron(s). One atom of the element loses electron(s) while the other atom gains electron(s).

The compound Magnesium chloride is an ionic compound . The bond between an atom of magnesium and 2 atoms of chlorine is an ionic bonding.

The valency electron of magnesium is 2 electron , for the atom of magnesium to  attain octet rule, it will easily lose it 2 electrons to the chlorine atoms.

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