1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
11111nata11111 [884]
3 years ago
11

How would you prepare 100 ml of 0.4 M MgSO4 from a stock solution of 2 M MgSO4?

Chemistry
1 answer:
miss Akunina [59]3 years ago
7 0
OK, so to answer this question, you will simply use the molality equation which is as follows:
<span>M1V1 = M2V2 
In the givens you have:
M1 = 2M
V1 is the unknown
M2 = 0.4M
V2 = 100 ml

</span>plug in the givens in the above equation:
<span>2 x V1 = 0.4 x 100 
</span>therefore:
V1 = 20 ml

Based on this: you should take 20 ml of the 2 M solution and make volume exactly 100 ml in a volumetric flask by diluting in water.

You might be interested in
1. Nitrogen, oxygen, and fluorine atoms all seem pretty similar, at first. How many valence electrons does an atom of each have?
matrenka [14]
Nitrogen is 5 valence electrons
oxygen is 6 valence electrons
fluorine is 7 electrons
6 0
3 years ago
What is an amorphous solid?
Gennadij [26K]

Answer:

The Answer is D: A solid with no repeating pattern in its structure

Explanation:

5 0
4 years ago
What is the most likely formula for an oxide formed between group a 1 atom x and oxygen
Marizza181 [45]
The most likely formula for an oxide formed between group 1a atom X and oxygen would be

X2O. - X is group 1a atom.
5 0
3 years ago
In an chemicalbreaction involving Fe and S, it was found that 45.2 g of Fes was produced. If the percent yield of the reaction i
saw5 [17]

Answer:

47.8 g

Explanation:

Remember the equation for percent yield:

% yield = actual / theoretical

We're given two of the values in the question, so plug n' play:

0.945 = 45.2 / theoretical

theoretical = 47.8 g

Keep in mind you can use mass here without converting to moles because we're working with products only. If you were given a mass of reactants, you would need to convert to moles and using a balanced chemical equation find the corresponding moles of product produced.

7 0
3 years ago
Predict which substance has greater molar entropy. Explain.(b) KClO3₃(s) or KClO₃(aq)
photoshop1234 [79]

KClO3 (aq) will have greater molar entropy than KClO3 (s) because molar entropy increases with increase in temperature.

As the temperature rises, the standard molar entropy of any substance rises. Entropy and a Single Substance's Temperature ” Entropy increases significantly when a solid turns into a liquid and when a liquid turns into a gas. The entropy of the liquid is lower than that of the gas. As a result, entropy rises in reactions that produce gaseous byproducts from solid or liquid reactants. When solid reactants produce liquid products, entropy also rises.

Learn more about Molar entropy here-

brainly.com/question/3627396

#SPJ4

5 0
1 year ago
Other questions:
  • You can determine the concentration of acids or bases in a solution by using___________.
    10·1 answer
  • I need help solving this for chemistry. Don’t know where to start:/
    11·1 answer
  • How do you sort bonds by polarity
    12·1 answer
  • Elements in the same period of the periodic table exhibit similar physical and chemical properties.
    6·1 answer
  • This element was named for the scientist who discovered the nucleus of the atom using gold foil
    5·2 answers
  • HELP POGGERS!!! I NEED HELP!!!!!!!!!! THIS IS NEEDED IN 10 MINS
    7·2 answers
  • Under conditions of constant temperature and amount of substance, a plot of pressure VS. volume for an ideal gas will result in:
    9·1 answer
  • Which terms describe plastics that can and potentially be recycled?
    7·1 answer
  • Heat moves from what source by convection and radiation?
    6·1 answer
  • The Geocentric and the Heliocentric models are descriptions of the universe known at the time when these models were developed.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!