Question

A gas occupies a volume of 750 mL at 101.3 kPa. What pressure (in kPa) is needed to decrease the volume to 250mL?

Answer 1

Answer:

The final pressure of the gas comes out to be 303.9 KPa

Explanation:

Initial volume of gas = V = 750 mL

Initial pressure of gas = P = 101.3 KPa

Final volume of gas = V' = 250 mL

Assuming final pressure of the gas to be P' KPa.

Assuming temperature to be kept constant.

The final pressure can be obtained by following expression shown below

$PV = P'V' \\101.3\textrm{ KPa}\times 750\textrm{ mL} = P' \times 250 \textrm{ mL} \\P' = 303.9 \textrm{ KPa}$

Final pressure of gas = 303.9 KPa