A gas occupies a volume of 750 mL at 101.3 kPa. What pressure (in kPa) is needed to decrease the volume to 250mL?
1 answer:
Answer:
The final pressure of the gas comes out to be 303.9 KPa
Explanation:
Initial volume of gas = V = 750 mL
Initial pressure of gas = P = 101.3 KPa
Final volume of gas = V' = 250 mL
Assuming final pressure of the gas to be P' KPa.
Assuming temperature to be kept constant.
The final pressure can be obtained by following expression shown below
Final pressure of gas = 303.9 KPa
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Answer: 6.
Explanation:
1) Aluminum
So each atom of aluminum lost 3 electrons to pass from 0 oxidation state to 3+ oxidation state.
2) Manganesium
So, each ion of Mn(2+) gained 2 electrons pass from 2+ oxidation state to 0.
3) Balance
Multiply aluminum half-reaction (oxidation) by 2 and multiply manganesium half-raction (reduction) by 3:
4) Net equation
Add the two half-equations:
As you see the left side has 2 Al, 3Mn, and 3*2 positive charges.
The right side has 2 Al, 3 Mn, and 2*3 positive charges.
So, the equation is balanced.
5) Count the number of electrons involved.
As you see 2 atoms of aluminum lost 6 electrons (3 each).
That is the answer to the question. 6 electrons will be lost.
Explanation:
1) Aluminum
So each atom of aluminum lost 3 electrons to pass from 0 oxidation state to 3+ oxidation state.
2) Manganesium
So, each ion of Mn(2+) gained 2 electrons pass from 2+ oxidation state to 0.
3) Balance
Multiply aluminum half-reaction (oxidation) by 2 and multiply manganesium half-raction (reduction) by 3:
4) Net equation
Add the two half-equations:
As you see the left side has 2 Al, 3Mn, and 3*2 positive charges.
The right side has 2 Al, 3 Mn, and 2*3 positive charges.
So, the equation is balanced.
5) Count the number of electrons involved.
As you see 2 atoms of aluminum lost 6 electrons (3 each).
That is the answer to the question. 6 electrons will be lost.