A gas occupies a volume of 750 mL at 101.3 kPa. What pressure (in kPa) is needed to decrease the volume to 250mL?
1 answer:
Answer:
The final pressure of the gas comes out to be 303.9 KPa
Explanation:
Initial volume of gas = V = 750 mL
Initial pressure of gas = P = 101.3 KPa
Final volume of gas = V' = 250 mL
Assuming final pressure of the gas to be P' KPa.
Assuming temperature to be kept constant.
The final pressure can be obtained by following expression shown below
Final pressure of gas = 303.9 KPa
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A molecular orbital that decreases the electron density between two nuclei is said to be <u>antibonding.</u>
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An asterisk (sigma*) is placed next to the corresponding kind of molecular orbital to indicate an antibonding orbital. The antibonding orbital known as * would be connected to sigma orbitals, as well as antibonding pi orbitals are known as * orbitals.
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Hence, the correct answer will be option (b)
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Answer: Reducing agent in the given reaction is .
Explanation:
A reducing agent is defined as an element which tends to lose electrons to other element leading to an increase in its oxidation number.
In the given reaction, oxidation state of sulfur in is +2 and
has 0 oxidation state.
In oxidation state of S is 2.5 and in
oxidation state of I is -1.
Since, an increase in oxidation state of S is occurring from +2 to +2.5. Hence, it is acting as a reducing agent.
Thus, we can conclude that reducing agent in the given reaction is .