Answer:
49.14%
Explanation:
The frequency of the heterozygous individuals in the population is therefore: 64/400 = 0.32
Using the Hardy Weingburg equation of a population is equilibrium = p2 + 2pq + q2 = 1
q2 = 0.32; Therefore q = 0.5657 –> alellic frequencies
If p + q = 1; Then p 1 – q = 1 – 0.5657 = 0.4343
Heterozygous individuals are represented by 2pq = 2 * 0.4343 * 0.5657 = 0.4914
0.4914 * 100 = 49.14% of the population which translates to 0.4914 * 400 = 196.56 (197) individuals
Answer:
550 milliliters of water is needed.
Explanation:
the student will need 550 milliliters of water for completing the whole experiment. 250 milliliters of water is needed for boiling purpose while on the other hand, 100 milliliters of water is needed for one process which can be repeated three times so the process needs 300 milliliters of water so by combining the 250 milliliters and 300 550 milliliters of water we get 550 milliliters of water for the whole experiment so we can say that the student needs 550 milliliters of water for the experiment.
An ion is an atom or molecule with a net electric charge due to the loss or gain of one or more electrons.
Hope this helps! ;)
The correct answers A false
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