Answer:
3.51 (round to the nearest hundreds)
Step-by-step explanation:
PART A
slope of the line passing through AC : (6-1)/(1-2) = 5/-1 = -5
equation of the line passing through B and perpendicular to AC:
y-3 = 1/5(x-3)
y-3 = 1/5x -3/5
y = 1/5 x - 3/5 + 3
y = 1/5 x + (-3+15)/5
y = 1/5 x + 12/5
PART B
line that passes through the points A and C
y-1 = -5(x-2)
y = -5x+10 + 1
y = -5x + 11
Interception of the lines
y = 1/5x + 12/5
y = -5x + 11
-5x + 11 = 1/5x + 12/5
-25x +55 = x + 12
26x = 43
x = 43/26
y = -5(43/26) + 11
y= -215/26 + 11
y = (-215+286)/26 = 71/26
D (1.65, 2.73)
PART C
AC = 
= 5,09902
BD = 
= 1,376735
PART D
AREA = (5,09902 * 1.376735)/2 = 3,509999
I believe the answer is correct
Answer:
82 nails
Step-by-step explanation:
4.97 and 5.03 are both one standard deviation from the mean...
z scores . 8413 and .1587
.8413 - .1587 = .6826 or 68.26 % of the nails are in this range
68.26 % * 120 = ~82 nails
Answer:
0.341 is the probability that the sample contains 1 or more rotten oranges.
Step-by-step explanation:
We are given the following information:
We treat rotten as a success.
Number of oranges = 75
Number of rotten orange = 6
P(Rotten orange) =
Then the number of rotten oranges follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 5
We have to evaluate:
0.341 is the probability that the sample contains 1 or more rotten oranges.
Answer:
20
Step-by-step explanation:
4 Cup's = 1 Quarter so do
4 x 5 because that is how many quarters you have and that is how you get the answer
